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2 years ago

Line CD passes through points C(3, –5) and D(6, 0). What is the equation of line CD in standard form?

2 answers:

3 0

$\text{The formula of a slope:}\ m=\dfrac{y_2-y_1}{x_2-x_1}\\\\\text{We have:}\\C(3;\ -5)\to x_1=3;\ y_1=-5\\D(6;\ 0)\to x_2=6;\ y_2=0\\\\\text{substitute}\\\\m=\dfrac{0-(-5)}{6-3}=\dfrac{5}{3}\\\\\text{The point-slope formula:}\ y-y_1=m(x-x_1)\\\\\text{substitute}\\\\y-(-5)=\dfrac{5}{3}(x-3)\\\\y+5=\dfrac{5}{3}x-5\ \ \ |-5\\\\\boxed{y=\dfrac{5}{3}x-10}$

NISA [10]2 years ago

3 0

= 5/2 x- 10.....................

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Another way of determining the same result: We want to find a scalar function $f(x,y,z)$ such that its gradient is equal to the given vector field, $\mathbf f(x,y,z)$ :

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