Answer:
The degrees of freedom are given by;

The significance level is 0.1 so then the critical value would be given by:

If the calculated value is higher than this value we can reject the null hypothesis that the arrivals are uniformly distributed over weekdays
Step-by-step explanation:
For this case we have the following observed values:
Mon 25 Tue 22 Wed 19 Thu 18 Fri 16 Total 100
For this case the expected values for each day are assumed:

The statsitic would be given by:

Where O represent the observed values and E the expected values
The degrees of freedom are given by;

The significance level is 0.1 so then the critical value would be given by:

If the calculated value is higher than this value we can reject the null hypothesis that the arrivals are uniformly distributed over weekdays
This can be mathematically expressed to
250 + X = 1075
where X represents the parts you produce before the shift ends
Transpose 250 to the other side by subtracting each side by 250
Thus, it goes like this
X = 1075 - 250
X = 825
You produced 825 parts in the middle of the shift.
Answer:
X=Y
Step-by-step explanation:
5x-5Y=
+5y=5y
5x=5y
divide both sides by 5
x=y
Answer:
there isnt enough info
Step-by-step explanation: