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Luda [366]
3 years ago
11

Need help finding the domain and range

Mathematics
1 answer:
pogonyaev3 years ago
3 0

Here are a few things you'll need to know for this question:

  • Domain: <u>The list of x-values that are possible on a line.</u>
  • Range: <u>The list of y-values that are possible on a line.</u>
  • Interval Notation: <u>Shows the domain/range using the endpoints</u>. Brackets mean that the endpoint is included, parentheses mean the endpoint is excluded. Ex: (2,10]. 2 is excluded, 10 is included.
  • Closed Circles: <u>The endpoint is included.</u>
  • Open Circles: <u>The endpoint is excluded.</u>

So firstly, let's look at the domain. We see that there is a closed circle at x = -2 and an open circle at x = 5. Using what we know, <u>the interval notation of the domain is [-2,5).</u>

Next, let's look at the range. We see that there is a closed circle at y = -5 and an open circle at y = 2. Using what we know, <u>the interval notation of the range is [-5,2).</u>

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9. Complete the reasons in the proof below.
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For a), this is clearly a given as it is literally to the right of where it says “Given:”
For b), since ON bisects ∠JOH, this means that it splits it into two separate angles - JON and HON, which are similar due to that bisects mean that it splits it equally into two halves
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For d), since AAS (angle-angle-side) congruence states that if there are two angles that are congruent (proved in a) and b) ) as well as that a side is congruent (proved in c) ), two triangles are congruent
For e), since two triangles are congruent, every side must have one side that it matches up to in the other triangle. As the opposite side of angle H is JO and the opposite side of angle J is OH, and ∠J=∠H, those two are congruent. As JN and HN are the two sides left, they must be congruent.

Feel free to ask further questions!
4 0
4 years ago
What is the slope of the line y= x/5+16
alexgriva [62]
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2/3 time 5
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