Answer: 1 < x < 25
<u>Step-by-step explanation:</u>
The sum of two sides must be GREATER than the third side.
a + b > c a + c > b b + c > a
12 + 13 > x 12 + x > 13 13 + x > 12
25 > x x > 1 x > -1
x < 25 1 < x
Length cannot be negative so disregard x > -1
We are left with 1 < x and x < 25
1 < x < 25
1/2 is half of a whole
whole= 1/1. 2/2, 3/3, 4/4 and so on
1/2 are numbers that can be simplify to halves= 1/2, 2/4, 3/6, 4/8, 5/10 and 1/2 are half of the denominator
Answer:
1.544*10⁹ Linebackers would be required in order to obtain the same density as an alpha particle
Step-by-step explanation:
Assuming that the pea is spherical ( with radius R= 0.5 cm= 0.005 m), then its volume is
V= 4/3π*R³ = 4/3π*R³ = 4/3*π*(0.005 m)³ = 5.236*10⁻⁷ m³
the mass in that volume would be m= N*L (L= mass of linebackers=250Lbs= 113.398 Kg)
The density of an alpha particle is ρa= 3.345*10¹⁷ kg/m³ and the density in the pea ρ will be
ρ= m/V
since both should be equal ρ=ρa , then
ρa= m/V =N*L/V → N =ρa*V/L
replacing values
N =ρa*V/L = 3.345*10¹⁷ kg/m³ * 5.236*10⁻⁷ m³ /113.398 Kg = 1.544*10⁹ Linebackers
N=1.544*10⁹ Linebackers
Lol just get a calculator and math paper. This is not cool, u aren't in college. Im in 7TH GRADE and I can do this garbage...
128, -512, 2048
Multiply by -4 to get each new term