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Aleksandr [31]
4 years ago
9

If the test statistic for a small sample difference of means test is t* = 2.045, we could reject the Null Hypothesis at alpha =

.05 for a one-tailed test with degrees of freedom equal to 6.
A. True
B. False
Computers and Technology
1 answer:
Free_Kalibri [48]4 years ago
8 0

Answer:

True

Explanation:

Using the t-distribution table, the critical value for a one-tailed test with 6 degrees of freedom and 0.05 significance level is 2.447

Conclusion:

Reject the null hypothesis because the test statistic 2.045 is less than the critical value 2.447

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Answer:

\textsf{\large{\underline{Solution}:}}

The given problem is solved using language - Python.

def f(x):

   new_list=[]

   for i in x:

       if i%2==0:

           new_list.append(i//2)

       else:

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   return new_list

   

my_list=list(range(1,6))

print('Original List:',my_list)

my_list=f(my_list)

print('Modified List:',my_list)

\textsf{\large{\underline{Logic}:}}

  1. Create a new list.
  2. Iterate over the list passed into the function.
  3. Check if the element is even or not. If true, append half the value of element in the list.
  4. If false, append twice the value of the element in the list.
  5. At last, return the new list.

There is another way of doing this - By using map() function.

—————————————————————————————

def f(x):

   return list(map(lambda x:x//2 if x%2==0 else 2*x,x))

   

my_list=list(range(1,6))

print('Original List:',my_list)

my_list=f(2my_list)

print('Modified List:',my_list)

—————————————————————————————

\textsf{\large{\underline{O{u}tput}:}}

Original List: [1, 2, 3, 4, 5]

Modified List: [2, 1, 6, 2, 10]

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