1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Yakvenalex [24]
2 years ago
15

Suppose we used an internet addressing protocol that used 4 bits to encode a single address. How many devices would be supported

on the internet? how many unique addresses would there be?.
Computers and Technology
1 answer:
trapecia [35]2 years ago
4 0

The number of unique addresses that can be supported on the devices with 4 bits will be 16.

<h3>What is an internet protocol?</h3>

An internet protocol is a protocol that describes the structure of an internet address and then allocates a unique address to each internet-connected device.

However, we need to understand that one bit can only support four addresses.

Therefore, we can conclude that the number of unique addresses that would supported by 4 bits will be 16.

Learn more about Internet protocol here:

brainly.com/question/18215126

You might be interested in
How does beamforming improve network service?
fenix001 [56]

Beamforming can improve network service by using device locations to better target service signals.

This is because, beamforming helps to deliver higher signal quality to the target receiver.

<h3>What is beamforming?</h3>

beamforming can be regarded as application of different radiating elements that is transmitting the same signal.

This signal is usually identical in wavelength and phase, and  by reinforcing the waves in a specific direction the goal can be acheived.

Learn more about beamforming at:

brainly.com/question/12809344

7 0
2 years ago
Identify the equation that translates Y = In(x) five units down.​
Tatiana [17]
Y=In(x)-5
hopefully it’s right :)
4 0
2 years ago
Insert a formula that references the appropriate worksheets in cell a3 on the offensive totals worksheet to calculate total pass
Mnenie [13.5K]

In excel spreadsheets, you need to consider specifying relationships between the information you have stored in your spreadsheets when creating formulas. The elements that will help you understand using spreadsheet are the constants, operators, references and functions. This will enable you to use the formulas, without hassle in spreadsheets.

3 0
3 years ago
A function test() that would take three integervalues x, y and z (as
marta [7]

Answer: The c++ program to implement test() method is given below.

#include <iostream>

using namespace std;

int test(int a, int b, int c);

int main() {

   int x, y, z;

   cout<<"This program displays the largest number."<<endl;

       cout<<"Enter first number"<<endl;

       cin>>x;

       cout<<"Enter second number"<<endl;

       cin>>y;

       cout<<"Enter third number"<<endl;

       cin>>z;

   int max = test(x, y, z);

   cout<<"The largest number is "<<max<<endl;

   return 0;

}

int test(int a, int b, int c)

{

   if((a>b)&&(a>c))

       return a;

 

   else if((b>a)&&(b>c))

           return b;

           

   else if((c>b)&&(c>a))

           return c;

     

}

OUTPUT

This program displays the largest number.

Enter first number

12

Enter second number

0

Enter third number

-87

The largest number is 12

Explanation:

The method test() is declared as follows.

<em>int test(int a, int b, int c);</em>

The method is declared with return type int since it returns an integer, i.e., the largest of the three parameters.

This program is designed to accept 0 and all values of integers. Hence, input is not tested for validity. It is assumed that the user enters only numerical values.

The program declares and uses three integer variables to store the user input.

<em>int x, y, z;</em>

The method test() is designed to accept three integer parameters. This method is called once the user enters three numbers for comparison.

<em>int test(x, y, z);</em>

These numbers are compared in order to return the largest number.

No variable is used for comparison. The method simply compares the numbers using multiple if-else statements.

<em>if((a>b)&&(a>c))</em>

<em>        return a;</em>

The same comparison logic is applied for other two input values.

The largest number is returned to the calling function which is main() in this program. This value is stored in the integer variable, max, declared in the main() method. The variable max is declared and initialized simultaneously.

<em>int max = test(x, y, z);</em>

This value is then displayed on the screen.

<em>cout<<"The largest number is "<<max<<endl;</em>

4 0
3 years ago
1. The following programs require using arrays. For each, the input comes from standard input and consists of N real numbers bet
Mamont248 [21]

Answer:

import java.util.*;

import java.io.BufferedReader;

import java.io.IOException;

import java.io.InputStreamReader;

import java.util.Arrays;

class GFG

{

  // Function for calculating mean

  public static double findMean(double a[], int n)

  {

      int sum = 0;

      for (int i = 0; i < n; i++)

          sum += a[i];

 

      return (double)sum / (double)n;

  }

  // Function for calculating median

  public static double findMedian(double a[], int n)

  {

      // First we sort the array

      Arrays.sort(a);

      // check for even case

      if (n % 2 != 0)

      return (double)a[n / 2];

 

      return (double)(a[(n - 1) / 2] + a[n / 2]) / 2.0;

  }

  public static double findMode(double a[], int n)

{

// The output array b[] will

// have sorted array

//int []b = new int[n];

 

// variable to store max of

// input array which will

// to have size of count array

double max = Arrays.stream(a).max().getAsDouble();

 

// auxiliary(count) array to

// store count. Initialize

// count array as 0. Size

// of count array will be

// equal to (max + 1).

double t = max + 1;

double[] count = new double[(int)t];

for (int i = 0; i < t; i++)

{

count[i] = 0;

}

 

// Store count of each element

// of input array

for (int i = 0; i < n; i++)

{

count[(int)(10*a[i])]++;

}

 

// mode is the index with maximum count

double mode = 0;

double k = count[0];

for (int i = 1; i < t; i++)

{

if (count[i] > k)

{

k = count[i];

mode = i;

}

}

return mode;

}

public static double findSmallest(double [] A, int total){

Arrays.sort(A);

return A[0];

}

 

public static void printAboveAvg(double arr[], int n)

{

 

// Find average

double avg = 0;

for (int i = 0; i < n; i++)

avg += arr[i];

avg = avg / n;

 

// Print elements greater than average

for (int i = 0; i < n; i++)

if (arr[i] > avg)

System.out.print(arr[i] + " ");

System.out.println();

}

 

public static void printrand(double [] A, int n){

Arrays.sort(A);

for(int i=0;i<n;i++){

System.out.print(A[0]+"/t");

}

System.out.println();

}

 

public static void printHist(double [] arr, int n) {

 

for (double i = 1.0; i >= 0; i-=0.1) {

System.out.print(i+" | ");

for (int j = 0; j < n; j++) {

 

// if array of element is greater

// then array it print x

if (arr[j] >= i)

System.out.print("x");

 

// else print blank spaces

else

System.out.print(" ");

}

System.out.println();

}

// print last line denoted by ----

for(int l = 0; l < (n + 3); l++){    

System.out.print("---");

}

 

System.out.println();

System.out.print(" ");

 

for (int k = 0; k < n; k++) {

System.out.print(arr[k]+" ");

}

}

  // Driver program

  public static void main(String args[]) throws IOException

  {

      //Enter data using BufferReader

BufferedReader br = new BufferedReader(new InputStreamReader(System.in));

double [] A = new double[100];

int i=0;

System.out.println("Enter the numbers(0.0-1.0) /n Enter 9 if u have entered the numbers. /n");

do

{

A[i++]=Double.parseDouble(br.readLine());

}while(A[i-1]==9);

      i--;

      System.out.println("Average = " + findMean(A,i) );

      System.out.println("Median = " + findMedian(A,i));

      System.out.println("Element that occured most frequently = " + findMode(A,i));

      System.out.println("number closest to 0.0 =" + findSmallest(A,i));

      System.out.println("Numbers that are greater than the average are follows:");

      printAboveAvg(A,i);

      System.out.println("Numbers in random order are as follows:");

      printrand(A,i);

      System.out.println("Histogram is bellow:");

      printHist(A,i);

  }

}

Explanation:

3 0
3 years ago
Other questions:
  • Which does an icon on the desktop signify?
    12·1 answer
  • The series of events that make up a story is called
    6·2 answers
  • For this exercise, you'll use the Rectangle class below (you can assume that the length and width are measured in feet).
    12·1 answer
  • How can i address inv file in c for open it?
    13·1 answer
  • Erewrxdnnefwn q wedsvd
    6·1 answer
  • Different between desktop application and web application ?​
    9·1 answer
  • Designing a video game takes tons of creativity. What inspires your personal creativity and ideas for video games? Explain and g
    15·1 answer
  • Which line of code in this program is MOST likely to result in an error
    15·2 answers
  • You need to pay an Internet Service Provider (ISP) for services rendered. Which payment technology would you use?
    10·1 answer
  • What what do these two parts of the lift do ​
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!