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Yakvenalex [24]
2 years ago
15

Suppose we used an internet addressing protocol that used 4 bits to encode a single address. How many devices would be supported

on the internet? how many unique addresses would there be?.
Computers and Technology
1 answer:
trapecia [35]2 years ago
4 0

The number of unique addresses that can be supported on the devices with 4 bits will be 16.

<h3>What is an internet protocol?</h3>

An internet protocol is a protocol that describes the structure of an internet address and then allocates a unique address to each internet-connected device.

However, we need to understand that one bit can only support four addresses.

Therefore, we can conclude that the number of unique addresses that would supported by 4 bits will be 16.

Learn more about Internet protocol here:

brainly.com/question/18215126

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Answer:

When the element is not found we return -1.

Explanation:

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Q.No.3 b. (Marks 3)
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2 years ago
Write a C program that reads two hexadecimal values from the keyboard and then stores the two values into two variables of type
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Solution :

#include  $$

#include $$

#include $$

//Converts $\text{hex string}$ to binary string.

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{

 

long $\text{int i}$ = 0;

char *string = $(\text{char}^ *) \ \text{malloc}$(sizeof(char) * 9);

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strcat(string, "0011");

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$\text{case '4'}:$

strcat(string, "0100");

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$\text{case '5'}:$

strcat(string, "0101");

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strcat(string, "0110");

break;

$\text{case '7'}:$

strcat(string, "0111");

break;

$\text{case '8'}:$

strcat(string, "1000");

break;

$\text{case '9'}:$

strcat(string, "1001");

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case 'A':

case 'a':

strcat(string, "1010");

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case 'B':

case 'b':

strcat(string, "1011");

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case 'C':

case 'c':

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case 'D':

case 'd':

strcat(string, "1101");

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case 'E':

case 'e':

strcat(string, "1110");

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case 'F':

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return string;

}

 

int main()

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//Input 2 numbers p and n.

int p,n;

scanf("%d",&p);

scanf("%d",&n);

//keep j as length of str2

int j=strlen(str2),i;

//Now replace n digits after p of str1

for(i=0;i<n;i++){

str1[p+i]=str2[j-1-i];

}

//Now, i have used c library strtol

long ans = strtol(str1, NULL, 2);

//print result.

printf("%lx",ans);

return 0;

}

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Answer:

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