Answer:
d(apart are the ships)=42.8 meters
Step-by-step explanation:
Given data
h (height)=38m
Ф₁=53°
Ф₂=28°
d(how far apart are the ships)=?
Solution
d₅₃°(distance to ship at 53°)=h/tanФ₁
d₅₃°=38/tan(53°)
d₅₃°=28.6m
now
d₂₈°(distance to ship at 28°)=h/tanФ₂
d₂₈°=38/tan(28°)
d₂₈°=71.4m
d(apart are the ships)=d₂₈°-d₅₃°
d(apart are the ships)=71.4-28.6
d(apart are the ships)=42.8 meters
The answer is d. I believe it was for mine
<h3>
Answer:</h3>
-5y +1
<h3>
Step-by-step explanation:</h3>
Let the polynomial to be subtracted be represented by Q. Then you want ...
... (y^2 -5y +1) -Q = y^2
... (y^2 -5y +1) = y^2 +Q . . . . add Q
... (y^2 -5y +1) -y^2 = Q . . . . .subtract y^2
... -5y +1 = Q . . . . . . . . . . . . . simplify
The polynomial to be subtracted is -5y +1.
