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3 years ago

I need to give an equation for an absolute value function that has a minimum. How do I determine that it has a minimum?.

1 answer:

5 0

To determine the minimum of an equation, we derive the equation using differential calculus twice (or simply take the second derivative of the function). If the second derivative is greater than 0, then it is minimum; else, if it is less than 1, the function contains the maximum. If the second derivative is zero, then the inflection point is identified.

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In the early months of some year one site added 0.2 million new accounts everyday. At this rate, how many days would be needed t

WITCHER [35]

60 days, I think. Sixty times zero point two is twelve.

3 0

3 years ago

Select all tables thaf represent A proportional relationship between x and y.

Whitepunk [10]

A is the answer babygirl.

4 0

3 years ago

Consider the equation below

s344n2d4d5 [400]

Answer: B

Step-by-step explanation:

Let's solve the given equation. Then we can see which other equation has the same answer.

-5n+31=-14n-5

36=-9n

n=-4

We need to fina another equation that gives n=4 as the answer.

A. Incorrect

3-6n+3n=-3+4-4n

3-3n=1-4n

n=-2

B. Correct

$\frac{11}{4} n+2=-3+\frac{3}{2}n$

$\frac{5}{4}n=-5$

$n=-4$

C. Incorrect

1=0.75n+3.25

-2.25=0.75n

n=-3

D. Incorrect

-1-22n=-20n-9

8=2n

n=4

7 0

2 years ago

A research study investigated differences between male and female students. Based on the study results, we can assume the popula

garri49 [273]

Using the normal distribution and the central limit theorem, it is found that the interval that contains 99.44% of the sample means for male students is (3.4, 3.6).

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.

After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

In this problem:

The mean is of $\mu = 3.5$ .

The standard deviation is of $\sigma = 0.5$ .

Sample of 100, hence $n = 100, s = \frac{0.5}{\sqrt{100}} = 0.05$

The interval that contains 95.44% of the sample means for male students is between Z = -2 and Z = 2, as the subtraction of their p-values is 0.9544, hence:

Z = -2:

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$