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3 years ago

11

I need to give an equation for an absolute value function that has a minimum. How do I determine that it has a minimum?.

1 answer:

tatyana61 [14]3 years ago

5 0

To determine the minimum of an equation, we derive the <span>equation using differential calculus twice (or simply </span><span>take the second derivative of the function). If the </span><span>second derivative is greater than 0, then it is minimum; </span><span>else, if it is less than 1, the function contains the </span><span>maximum. If the second derivative is zero, then the </span><span>inflection point </span><span>is</span><span> identified.</span>

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What is midpoint 85 90?

monitta

The midpoint of 85 and 90 is 87

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3 years ago

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lisov135 [29]

plug in -2 for x

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3 years ago

Find the other endpoint of the line segment with the given endpoint and midpoint: endpoint(1.7, -4.6) midpoint (-7.5, 0.3).. (ne

Sergio [31]

Answer:

(- 16.7, 5.2 )

Step-by-step explanation:

let the coordinates of the endpoint be (x , y )

using the midpoint formula

consider the x- coordinate

$\frac{1}{2}$ (x + 1.7) = - 7.5 ( multiply both sides by 2 )

x + 1. 7 = - 7.5 ( subtract 1.7 from both sides )

x = - 16.7

consider the y-coordinate

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3 0

3 years ago

How to put y =2x+1 on a table

valentina_108 [34]

Answer:

I put the table below

Step-by-step explanation:

Find x and y values for the equation.

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7 0

3 years ago

Could you help plz.

I am Lyosha [343]

Cost of each bags of flour = $2.50

Cost of each bags of butter = $3.75

Solution:

Let f be the bags of flour and b be the pounds of butter.

Cost of 20 bags of flour 16 pound of butter = 110

⇒ 20f + 16b = 110 -------------------- (1)

Cost of 30 bags of flour 12 pound of butter = 120

⇒ 30f + 12b = 120 -------------------- (2)

Equation (1) and (2) are the system of equations.

(2) ⇒ 30f + 12b = 120

Subtract 30f from both sides.

⇒ 12b = 120 – 30f

Divide by 12 on both sides.

$$\Rightarrow b =\frac{120-30f}{12}$ -------------------- (3)

Substitute (3) in (1).

$$20f+16\left(\frac{120-30f}{12}\right)=110$

$$20f+4\left(\frac{120-30f}{3}\right)=110$

$$20f+4(40-10f)=110$

$$20f+160-40f=110$

Subtract 160 from both sides.

$$-20f=-50$

Divide by –20, we get

$$f=\frac{5}{2}$

f = 2.50

Substitute f = 2.5 in equation (3), we get

$$\Rightarrow b =\frac{120-30(2.50)}{12}$

$$b=\frac{15}{4}$

b = 3.75

Cost of each bags of flour = $2.50

Cost of each bags of butter = $3.75

7 0

3 years ago