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Lelechka [254]
3 years ago
11

Five less than 25% of a number is twice the difference of the number and 14. Write an equation that could be used to find the nu

mber, n.
Mathematics
1 answer:
Dmitriy789 [7]3 years ago
3 0

Answer:

(n/4) - 5  =  2(n-14)

Step-by-step explanation:

let the number be n

"25% of n" : (25/100)n = n/4

"Five less than 25% of n" : (n/4) - 5  

"difference between the number and 14" : n - 14

" twice the difference between the number and 14" : 2(n-14)

Assembling all the parts:

(n/4) - 5  =  2(n-14)

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How can we find the measure of an exterior angle if we know the measurement of an interior angle
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Show work and explain with formulas.
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20 Answer: a₁ = 4

<u>Step-by-step explanation:</u>

a_n=324,\ r=3,\ n=5\\\\a_n=a_1 \cdot r^{n-1}\\\\324=a_1\cdot 3^{5-1}\\\\\dfrac{324}{3^4}=a_1\\\\\dfrac{324}{81}=a_1\\\\\large\boxed{4}=a_1

21 Answer: n = 13

<u>Step-by-step explanation:</u>

a_n=\dfrac{1}{64},\ a_1=64,\ r=\dfrac{1}{2}\\\\a_n=a_1 \cdot r^{n-1}\\\\\dfrac{1}{64}=64\cdot \bigg(\dfrac{1}{2}\bigg)^{n-1}\\\\\dfrac{1}{64\cdot 64}=\bigg(\dfrac{1}{2}\bigg)^{n-1}\\\\\dfrac{1}{2^6\cdot 2^6}=\dfrac{1}{2^{n-1}}\\\\6+6=n-1\\\\\large\boxed{13}=n

22 Answer: n = 5

<u>Step-by-step explanation:</u>

a_n=48,\ a_1=1875\ r=\dfrac{2}{5}\\\\a_n=a_1 \cdot r^{n-1}\\\\48=1875\cdot \bigg(\dfrac{2}{5}\bigg)^{n-1}\\\\\dfrac{48}{1875}=\bigg(\dfrac{2}{5}\bigg)^{n-1}\\\\\dfrac{16}{625}=\bigg(\dfrac{2}{5}\bigg)^{n-1}}\\\\\bigg(\dfrac{2}{5}\bigg)^4=\bigg(\dfrac{2}{5}\bigg)^{n-1}}\\\\4=n-1\\\\\large\boxed{5}=n

6 0
3 years ago
Read 2 more answers
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