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2 years ago

8

Please i need this to be done. The end of the marking period is Friday and i have until tomorrow to do some of this can anyone h

elp??

1 answer:

natita [175]2 years ago

6 0

Good luck I answered on the other one

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The dDifference in hours between full times and the part timers to work three hours a day is 2 working hours how many hours per

hram777 [196]

full timers work 5 hours a day whereas Part timers work 3 hours a day!

<u>Step-by-step explanation:</u>

Here we have , The difference in hours between full times and the part timers to work three hours a day is 2 working hours . We need to find that how many hours per day to full timers work . Let's find out:

Let full timers work x hours , Part time workers work 3 hours a day , According to question, difference in hours between full times and the part timers to work three hours a day is 2 working hours i.e.

⇒ $x-3 = 2$

Adding 3 to make x term alone :

⇒ $x-3+3 = 2+3$

⇒ $x=5$

Therefore, full timers work 5 hours a day whereas Part timers work 3 hours a day!

4 0

3 years ago

Express the system as AX = B; then solve using matrix inverses

Wittaler [7]

Answer with explanation:

1. The given equations are

3x -5 y=2

-x+2 y= 0

⇒The matrix in the form of , AX=B, is

$A=\left[\begin{array}{cc}3&-5\\-1&2\end{array}\right] ,\\\\ X=\left[\begin{array}{c}x&y\end{array}\right],\\\\B=\left[\begin{array}{c}2&0\end{array}\right]$

$\rightarrow X=A^{-1}B\\\\\rightarrow X=\frac{Adj.A}{|A|}\times B$

Adj.A=Transpose of cofactor of Matrix A

$Adj.A=\left[\begin{array}{cc}2&1\\5&3\end{array}\right] ,\\\\ |A|=6-5\\\\|A|=1\\\\\left[\begin{array}{c}x&y\end{array}\right]=\left[\begin{array}{cc}2&5\\1&3\end{array}\right] \times \left[\begin{array}{c}2&0\end{array}\right]\\\\x=4, y=2$

2.

The given equations are

x+y-z=2

x+z=7

2 x +y+z=13

⇒The matrix in the form of , AX=B, is

$A=\left[\begin{array}{ccc}1&1&-1\\1&0&1\\2&1&1\end{array}\right]\\\\ X=\left[\begin{array}{ccc}x\\y\\z\end{array}\right]\\\\B= \left[\begin{array}{ccc}2\\7\\13\end{array}\right]\\\\\rightarrow X=A^{-1}B\\\\\rightarrow X=\frac{Adj.A}{|A|}\times B\\\\a_{11}=-1,a_{12}=1,a_{13}=1,a_{21}=-2,a_{22}=3,a_{23}=1,a_{31}=1,a_{32}=-2,a_{33}=-1\\\\|A|=1\times(0-1)-1\times(1-2)-1\times(1-0)\\\\=-1+1-1\\\\|A|=-1\\\\Adj.A=\left[\begin{array}{ccc}-1&-2&1\\1&3&-2\\1&1&-1\end{array}\right]$

$\frac{Adj.A}{|A|}=\left[\begin{array}{ccc}1&2&-1\\-1&-3&2\\-1&-1&1\end{array}\right]\\\\X=A^{-1}B\\\\\left[\begin{array}{ccc}x\\y\\z\end{array}\right]=\left[\begin{array}{ccc}1&2&-1\\-1&-3&2\\-1&-1&1\end{array}\right]\times\left[\begin{array}{ccc}2\\7\\13\end{array}\right]\\\\x=3,y=3,z=4$

7 0

3 years ago

Is 3/4 greater than 7/8?

yKpoI14uk [10]

3/4 = (2*3) / (2* 4) = 6/8

7/8.

Is 3/4 greater than 7/8?
Is like asking is 6/8 greater than 7/8? Because 3/4 is equivalent to 6/8.

The answer is No.

3 0

3 years ago

Read 2 more answers

Find the value of x.

sp2606 [1]

x = 64°

Step-by-step Explanation

x = 1/2[(360° - 2*58°)-2*58°]

x = 1/2[(360° - 2*58°) - 2*58°]

x = 1/2[(360° - 116°) - 116°]

x = 1/2[244° - 116°]

x = 1/2[128°]

x = 64°

8 0

3 years ago

The second one I don’t know it

loris [4]

Answer:

The third one $\sqrt[3]{15}$

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers