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2 years ago

A bowl contained 49.7 grams of salt. Then, Charlie poured in another 41.14 grams. How much salt does the bowl contain now?

Mathematics

1 answer:

professor190 [17]2 years ago

6 0

Answer:

90.84

Step-by-step explanation:

49.7+41.14= 90.84

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2/5 of 60 please help

klasskru [66]

Answer:

60/5 is equal to 12. so 12 x 2= 24, and 5 x 12=60, so 24/60, or just 24

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

The average number of customers per day increased 25 percent during the sale. If the average number of customers per day before

Rasek [7]

Answer:

The average number of customers per day during the sale was 150.

Step-by-step explanation:

This question can be solved using a rule of three.

Before the sale, the average number of customers per day was 120, which is 100% = 1.

Now, there are x customers, and since it is an increase of 25%, it is 100+25 = 125% = 1.25. So

120 - 1

x - 1.25

x = 1.25*120 = 150

The average number of customers per day during the sale was 150.

6 0

3 years ago

Danni counted 48 apples in a basket of apples. The basket actually contained 46 apples. What is the percent error?

enot [183]

The answer would be 4.2%

5 0

3 years ago

HELP FAST PLEASE I'LL MARK YOU BRAINLIEST What is the slope of a line perpendicular to the line whose equation is x+2y=14. Fully

sashaice [31]

Turn it into slope-intercept form.
2y = -x + 14
y = -x/2 + 7
The slope is -1/2.
Perpendicular lines have slopes that are opposite reciprocal, so the slope of the perpendicular line is 2.

7 0

3 years ago

Naval intelligence reports that 4 enemy vessels in a fleet of 17 are carrying nuclear weapons. If 9 vessels are randomly targete

icang [17]

Answer:

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

Step-by-step explanation:

The vessels are destroyed without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

Fleet of 17 means that $N = 17$

4 are carrying nucleas weapons, which means that $k = 4$

9 are destroyed, which means that $n = 9$

What is the probability that more than 1 vessel transporting nuclear weapons was destroyed?

This is:

$P(X > 1) = 1 - P(X \leq 1)$

In which

$P(X \leq 1) = P(X = 0) + P(X = 1)$

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,17,9,4) = \frac{C_{4,0}*C_{13,9}}{C_{17,9}} = 0.0294$

$P(X = 1) = h(1,17,9,4) = \frac{C_{4,1}*C_{13,8}}{C_{17,9}} = 0.2118$

Then

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.0294 + 0.2118 = 0.2412$

$P(X > 1) = 1 - P(X \leq 1) = 1 - 0.2412 = 0.7588$

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

8 0

2 years ago