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Verdich [7]
2 years ago
6

PLS HELP ASAP. QUESTION IN PICTURE

Mathematics
1 answer:
Anuta_ua [19.1K]2 years ago
4 0

Answer: 50 degrees

Step-by-step explanation:

This is actually quite simple using the exterior angle theory

"The exterior angle theorem states that the measure of an exterior angle is equal to the sum of the measures of the two remote interior angles of the triangle"

In this case the exterior angle is 120 degrees, basically what the theorem states is that it the angle that you see outside the triangle equals the angle measurements of the 2 angles opposite of it, so just create an equation because you know 2 of the variables

120=70+x

120-70=x

Angle x = 50 degrees

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Solve . 3/27 = w/54
WINSTONCH [101]

\frac{3}{27}=\frac{w}{54}    Multiply 54 to both sides to get "w" by itself

(54)\frac{3}{27}=\frac{w}{54}(54)

\frac{162}{27} =w

6 = w

6 0
3 years ago
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kondor19780726 [428]

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6 0
3 years ago
What is the sum of a common geometric series if the first term is 8 and the common ratio is 1/2?
stealth61 [152]

Answer:  A

Step-by-step explanation:

The sum to infinity of a geometric series is

S (∞ ) = \frac{a}{1-r} ( - 1 < r < 1 )

where a is the first term 8 and r is the common ratio, hence

S(∞ ) = {8}{1-\{1}{2} } = {8}{1}{2} } = 16

6 0
3 years ago
Please help me it is an easy question
Ugo [173]

Answer:

200 yd²

Step-by-step explanation:

A = 17 yd

B  = 15 yd

C = 2 yd

D = 8 yd

b) Area of rectangle = length * width

 \sf Area \ of \ 2 \ triangle = 2*  \dfrac{1}{2}* base * height = base* height\\\\

Area of right triangular prism = Areas of two triangle +  area of the upper rectangle + area of middle rectangle + area of below rectangle

          = 8 * 15 +  17 * 2 + 15 *2 + 8*2

          = 120 + 34 + 30 + 16

          = 200 yd²

5 0
2 years ago
Consider three events A, B and C with following properties.
lisov135 [29]
By the inclusion/exclusion principle,

\mathbb P(D)=\mathbb P(A\cup B\cup C)
\mathbb P(D)=\mathbb P(A)+\mathbb P(B)+\mathbb P(C)-\bigg(\mathbb P(A\cap B)+\mathbb P(A\cap C)+\mathbb P(B\cap C)\bigg)+\mathbb P(A\cap B\cap C)
\mathbb P(D)=\dfrac14+\dfrac16+\dfrac14-\dfrac39+\dfrac1{13}
\mathbb P(D)=\dfrac{16}{39}\neq1

So the union of A, B, and C does not constitute the entire sample space.
5 0
3 years ago
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