Answer:
D) observation that certain tumor-suppressor genes and oncogenes are involved in a sequential manner in the development of colon cancer
Explanation:
Cancer is defined as the abnormal growth of cells of the body. These cells multiply/replicate without control thereby forming a lump or tumor.
Cancer growth has 5 stages and they go though different multi level steps.Different finding backs this up and it includes observation about certain tumor-suppressor genes and oncogenes being involved in a sequential manner in the development of colon cancer.
<em>G1, S and G2 phases are all cumulatively referred to as interphase involving the growth of a cell and the replication of its DNA. Initially in G1 phase, the cell grows physically and increases the volume of both protein and organelles. In S phase, the cell copies its DNA to produce two sister chromatids and replicates its nucleosomes. Finally, G2 phase involves further cell growth and organisation of cellular contents. The S phase of a cell cycle occurs during interphase, before mitosis or meiosis, and is responsible for the synthesis or replication of DNA. In this way, the genetic material of a cell is doubled before it enters mitosis or meiosis, allowing there to be enough DNA to be split into daughter cells. The S phase only begins when the cell has passed the G1 checkpoint and has grown enough to contain double the DNA. S phase is halted by a protein called p16 until this happens.</em>
Answer:
Double-stranded DNA
Explanation:
If a virus requires to transport its genome in the nucleus to produce viral protein then the viral genome content must be DNA. This DNA of the virus will use the RNA polymerase of the host cell and will first convert into mRNA in the nucleus.
Then the mRNA of the virus will come out of the nucleus because the protein synthesis takes place outside the nucleus and in the cytoplasm. So in the cytoplasm by using host translational machinery the viral mRNA will code for viral proteins. So the correct answer is double-stranded DNA.
Answer:
The correct answer would be 0.85 liters.
It can be explained with the help of unit rate that is, when the rate is expressed as the quantity of 1 for example, 5 meter per second, 5 liters per day et cetera.
In this case, unit rate (liter per day) can be calculated by dividing the total amount of water used by total number of days.
Amount of water used in 28 days = 23.8 liters
The amount of water used in one day = 
It comes out to be 0.85 liters per day or 850 milliliter per day.
