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lidiya [134]
3 years ago
13

38 degrees 2x degrees +6 degrees

Mathematics
1 answer:
ratelena [41]3 years ago
5 0
STEP
1
:
Pulling out like terms

Pull out like factors :

32 - 2x = -2 • (x - 16)

STEP
2
:

Equations which are never true:

2.1 Solve : -2 = 0

This equation has no solution.
A a non-zero constant never equals zero.
Solving a Single Variable Equation:

2.2 Solve : x-16 = 0

Add 16 to both sides of the equation :
x = 16

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Answer:28

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Please help me complete this !! 12points
Svet_ta [14]

Answer:

1.

x1=1

x2=3

y1=5

y2=1

midpoint= (x1+x2/2, y1+y2/2)=(1+3/2,5+1/2)=(2,3)

2.

x1=2

x2=4

y1=4

y2=6

midpoint= (x1+x2/2, y1+y2/2)=(2+4/2,4+6/2)=(3,5)

3.

x1= -2

x2=4

y1=4

y2= -6

midpoint= (x1+x2/2, y1+y2/2)=(-2+4/2,4-6/2)=(1,-1)

4.

x1=0

x2=0

y1=3

y2=5

midpoint= (x1+x2/2, y1+y2/2)=(0/2,3+5/2)=(0,4)

5.

x1= -2

x2=2

y1= -6

y2=6

midpoint= (x1+x2/2, y1+y2/2)=(-2+2/2,-6+6/2)=(0,0)

6.

x1=1

x2=4

y1=4

y2=5

midpoint= (x1+x2/2, y1+y2/2)=(1+4/2,4+5/2)=(5/2,9/2)

7.

x1=-3

x2=-4

y1=5

y2=5

midpoint= (x1+x2/2, y1+y2/2)=(-3-4/2,5+5/2)=(-7/2,5)

8.

x1=5

x2= -4

y1=2

y2=6

midpoint= (x1+x2/2, y1+y2/2)=(5-4/2,2+6/2)=(1/2,4)

3 0
3 years ago
2. What are the solutions to the quadratic equation
Svetlanka [38]

Answer:

The answer is x=5 and x=−5

x² - 25 = 0

(x-5)(x+5)=0

x²-5x+5x-25=0

x-5=0 x+5=0

x=5 or x=-5

8 0
3 years ago
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