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loris [4]
2 years ago
14

Dana ate 50 g of a 60% chocolate bar and Neel ate 75 g of a 40% chocolate bar.

Mathematics
2 answers:
Leokris [45]2 years ago
6 0

Answer:

Both eat equal chocolate

Radda [10]2 years ago
5 0

Answer:

they both ate the same amount

QUESTION REPHRASED:

<em>Dana ate 60% of a 50 g chocolate bar and Neel ate 40% of a 75 g chocolate bar. </em>

<em>Who ate more pure chocolate?</em>

Step-by-step explanation:

60% of 50g is<u> 30g</u>

40% of 75g is also <u>30g</u>

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If the function graphed is f(x), find f(1).
Crazy boy [7]
Locate 1 on the x axis. This is the horizontal number line. 

Draw a vertical line through 1 on the x axis. Extend this vertical line as far up and down as you can.

Notice how the vertical line crosses the blue curve. Mark this point. Then draw a horizontal line from this point to the y axis. The horizontal line will touch -4 on the y axis. So that means the point (1,-4) is on the curve.

If the input it is x = 1, then the output is y = -4

So that's why the answer is choice A
7 0
3 years ago
The market sells 1 dozen bagels
PIT_PIT [208]

Answer:

market

Step-by-step explanation:

<u>Market</u>

1 dozen bagels = 12 bagels

⇒ Cost per bagel = $7.00 ÷ 12 = $0.58 (nearest cent)

<u>Bagel shop</u>

Cost per bagel = $0.60

As  $0.58 < $0.60 the market is a better buy

3 0
2 years ago
A jar of marbles contains the following: two red marbles, three white marbles, five blue marbles, and one green marble.
Lady_Fox [76]

Answer:

5/11

Step-by-step explanation:

5 blue marbles and 11 total marbles

3 0
3 years ago
Solve the system of equations by finding the reduced row-echelon form of the augmented matrix for the system of equations.
Anuta_ua [19.1K]

Answer:

c

Step-by-step explanation:

First, we can transform this into a matrix. The x coefficients will be the first ones for each row, the y coefficients the second column, etc.

\left[\begin{array}{cccc}1&-2&3&-2\\6&2&2&-48\\1&4&3&-38\end{array}\right]

Next, we can define a reduced row echelon form matrix as follows:

With the leading entry being the first non zero number in the first row, the leading entry in each row must be 1. Next, there must only be 0s above and below the leading entry. After that, the leading entry of a row must be to the left of the leading entry of the next row. Finally, rows with all zeros should be at the bottom of the matrix.

Because there are 3 rows and we want to solve for 3 variables, making the desired matrix of form

\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right] for the first three rows and columns. This would make the equation translate to

x= something

y= something

z = something, making it easy to solve for x, y, and z.

Going back to our matrix,

\left[\begin{array}{cccc}1&-2&3&-2\\6&2&2&-48\\1&4&3&-38\end{array}\right] ,

we can start by removing the nonzero values from the first column for rows 2 and 3 to reach the first column of the desired matrix. We can do this by multiplying the first row by -6 and adding it to the second row, as well as multiplying the first row by -1 and adding it to the third row. This results in

\left[\begin{array}{cccc}1&-2&3&-2\\0&14&-16&-36\\0&6&0&-36\end{array}\right]

as our matrix. * Next, we can reach the second column of our desired matrix by first multiplying the second row by (2/14) and adding it to the first row as well as multiplying the second row by (-6/14) and adding it to the third row. This eliminates the nonzero values from all rows in the second column except for the second row. This results in

\left[\begin{array}{cccc}1&0&10/14&-100/14\\0&14&-16&-36\\0&0&96/14&-288/14\end{array}\right]

After that, to reach the desired second column, we can divide the second row by 14, resulting in

\left[\begin{array}{cccc}1&0&10/14&-100/14\\0&1&-16/14&-36/14\\0&0&96/14&-288/14\end{array}\right]

Finally, to remove the zeros from all rows in the third column outside of the third row, we can multiply the third row by (16/96) and adding it to the second row as well as multiplying the third row by (-10/96) and adding it to the first row. This results in

\left[\begin{array}{cccc}1&0&0&-5\\0&1&0&-6\\0&0&96/14&-288/14\end{array}\right]

We can then divide the third row by -96/14 to reach the desired third column, making the reduced row echelon form of the matrix

\left[\begin{array}{cccc}1&0&0&-5\\0&1&0&-6\\0&0&1&-3\end{array}\right]

Therefore,

x=-5

y=-6

z=-3

* we could also switch the second and third rows here to make the process a little simpler

3 0
3 years ago
If f(x) = x + 1 and g(x) = 2x - 7, which expression is equivalent to [fog)(3)?
const2013 [10]
It would be 69 because if u add more to it there is not any other way but 69
8 0
3 years ago
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