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1 year ago

Dana ate 50 g of a 60% chocolate bar and Neel ate 75 g of a 40% chocolate bar.

Mathematics

2 answers:

Leokris [45]1 year ago

6 0

Answer:

Both eat equal chocolate

Radda [10]1 year ago

5 0

Answer:

they both ate the same amount

QUESTION REPHRASED:

Dana ate 60% of a 50 g chocolate bar and Neel ate 40% of a 75 g chocolate bar.

Who ate more pure chocolate?

Step-by-step explanation:

60% of 50g is 30g

40% of 75g is also 30g

You might be interested in

Rebotar Inc.makes basketballs.Their fixed costs are $3,450.

melomori [17]

Answer:

Since the profit is positive, Rebotar not only broke even, they had earnings.

Step-by-step explanation:

Function Modeling

The costs, incomes, and profits of Rebotar Inc. can be modeled by means of the appropriate function according to known conditions of the market.

It's known their fixed costs are $3,450 and their variable costs are $12 per basketball produced and sold. Thus, the total cost of Rebotar is:

C(x) = 12x + 3,450

Where x is the number of basketballs sold.

It's also known each basketball is sold at $25, thus the revenue (income) function is:

R(x) = 25x

The profit function is the difference between the costs and revenue:

P(x) = 25x - (12x + 3,450)

Operating:

P(x) = 25x - 12x - 3,450

P(x) = 13x - 3,450

If x=300 basketballs are sold, the profits are:

P(300) = 13(300) - 3,450

P(300) = 3,900 - 3,450

P(300) = 450

Since the profit is positive, Rebotar not only broke even, they had earnings.

8 0

2 years ago

The perimeter of △CDE is 55 cm. A rhombus DMFN is inscribed in this triangle so that vertices M, F, and N lie on the sides CD ,

ivanzaharov [21]

Answer:

CD = 14 cm; DE = 21 cm

Step-by-step explanation:

The perimeter is the sum of side lengths (in centimeters), so ...

CD + DE + CF + EF = 55

CD + DE + 8 + 12 = 55 . . . . . . . substittute for CF and EF

CD + DE = 35 . . . . . . . . . . . . . . subtract 20

___

The segment DF is a diagonal of the rhombus, so bisects angle D. That angle bisector divides ΔCDE into segments that are proportional. That is, ...

CD/DE = CF/EF = 8/12 = 2/3

___

So, we have two segments whose sum is 35 (cm) and whose ratio is 2 : 3. The total of "ratio units is 2+3=5, so each must stand for a length unit of 35/5 = 7 (cm). The sides are ...

CD = 2·7 cm = 14 cm

DE = 3·7 cm = 21 cm

Check

CD + DE = (14 +21) cm = 35 cm . . . . . matches requirements

7 0

2 years ago

Step 1: Choose ONE of the following triangles and complete the table below:

Archy [21]

The question is incomplete below you will find the missing part.

Step 1 : Choose ONE of the following triangles complete the table below:

1. Obtuse Scalene Triangle Translation to prove SSS Congruence

2. Isosceles Right Triangle Reflection to prove ASA Congruence

3. Equilateral Equiangular Triangle Rotation to prove SAS Congruence

Original Coordinate Point

Transformation Rule

Image Coordinate Points

A (1, 4) (x,y) -> (x+ ,y -) A’ ( , )

B ( 7,4) (x,y) -> (x+ ,y - ) B’ ( , )

C (8,9) (x,y) -> (x+ ,y -) C’ ( , )

The appropriate table is also shown below.

The triangles ABC and A'B'C' are congruent by SSS through Obtuse Scalene Triangle Translation because the corresponding sides are congruent

Two triangles are congruent if their size and shape are the same.

Now we have to transform the triangle,

The coordinates of the triangle ΔABC are given as:

A = (1, 4)

B = (7,4)

C = (8,9)

so the lengths of the sides of the triangle are given by

AB= √(7-1)²+(4-4)²= √6²= 6

BC= √(8-7)²+(9-4)²= √1²+5²= √1+25= √26

CA= √(8-1)²+(9-4)²= √7²+5²= √49+25= √74

In order to prove the SSS congruence, we have to transform the triangles under the following translation rule:

(x,y) -> (x -3, y +6)

in the above translation,

The triangle will be translated 3 units left

And then translated 6 units up.

So, we have the new coordination of the points of the translated triangle ΔA'B'C'

A' = (1-3, 4+6)

A' = (-2, 10)

B' = (7-3, 4+6)

B' = (4, 10)

C' = (8-3, 9+6)

C' = (5, 15)

Now

so the lengths of the sides of the triangle are given by

A'B'= √(4-(-2))²+(10-10)²= √6²= 6

B'C'= √(5-4)²+(15-10)²= √1²+5²= √1+25= √26

C'A'= √(-2-5)²+(10-15)²= √(-7)²+(-5)²= √49+25= √74

By comparing two triangles ΔABC and ΔA'B'C'

AB ≅ A'B'

BC ≅ B'C'

CA ≅ C'A'

Hence ΔABC ≅ A'B'C' (By S-S-S rule)

By the above transformation, the triangles ABC and A'B'C' are congruent by SSS because the corresponding sides are congruent as all the points are gone through the same transformation.

Learn more about the transformation

here: brainly.com/question/4289712

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