Answer:
How far did the ship travel between the two observations of the lighthouse = 9.29
Step-by-step explanation:
the first step to answer this question is drawing the illustration as the attachment.
P is the ship, R is the light house and Q is the bearing.
PR is the distance between the ship and the light house, PR = 10.5
∠P = 42.8°, ∠Q = 59.7°
Thus, ∠R = 180° - ∠P - ∠Q
= 180° - 42.8°- 59.7°
= 77.5°
PQ is the the distance of the ship moving. We can use the sinus equation
= 
= 
PQ = (
)(sin 59.7°)
= 9.29
Answer:
500.61
Step-by-step explanation:
5 multiplied by 100 = 500
1/10 = 0.1, So 6 multiplied by 0.1 = 0.6
1/100 = 0.01, So 1 multiplied by 1 = 0.01
500 + 0.6 + 0.01 = 500.61
For this case we have the following equation:
To clear w, we must follow the following steps:
1) The value of t multiplied by c pass to divide the other side of the equation:
2) the value of 1000 is passed to multiply to the other side of the equation:
Answer:
The cleared equation for w is:
Answer:
Setting
Step-by-step explanation:
