Based on the distance of the pitcher's mound from the home plate, the path of the ball, and the height the ball was hit, the distance the outfielder threw the ball is C. 183.0 ft.
<h3>How far did the outfielder throw the ball?</h3>
Based on the shape of a mound, the law of cosines can be used.
The distance the ball was thrown by the outfielder can therefore be d.
Distance is:
d² = 60.5² + 226² - (2 x 60.5 x 226 x Cos(39))
d ²= 33,484.42ft
Then find the square root:
d = √33,484.42
= 182.9874
= 183 ft
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Answer:
57,000 grams
Step-by-step explanation:
Answer: y = 6
Step-by-step explanation:
A square's area can be done by using s^2, where s is y in this case. Because there are 5 squares, the area of the figure is 5y^2. Because the area is also 180cm, 5y^2=180.
Then divide both sides of the equation by 5 to get y^2 = 36. Then square root both sides of the equation to get y = 6.
Hope it helps <3
Answer:
48
Step-by-step explanation:
We need to find the multiples of 8
8,16,24,32,40,48
48 is between 45 and 50 so he must have bought 48
