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Nitella [24]
2 years ago
10

What are the three components of personality, and how does personality develop in relation to each?.

SAT
1 answer:
Mumz [18]2 years ago
3 0

Answer:

He proposed three components to our personality: the id, ego, and superego. The job of the ego is to balance the sexual and aggressive drives of the id with the moral ideal of the superego. Freud also said that personality develops through a series of psychosexual stages.

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Ingrid is participating in a relay race. While jogging at 9 km/h, she tosses a relay stick at 16 km/h to her teammate, who is st
Katena32 [7]

Answer:

16 km/h

Explanation:

The relay stick would have the same velocity relative to Ingrid as the velocity she threw it because she threw it while running 9 km/h and the question asks for how fast it is moving RELATIVE to Ingrid, who also started off moving at 9 km/h.

Sorry if explanation is bad, this one was a bit of head scratcher for me to wrap my head around ig.

7 0
2 years ago
You would like to share information you found on a website. (select all that apply) you should: give credit to the source of the
kykrilka [37]

Answer:

At first glance, it may seem as if it's perfectly legal to copy content from a website. But is it? The short answer to this question is "no," unless you've obtained the author's permission. In fact, virtually all digital content enjoys the same copyright protections as non-digital, "offline" content.

Explanation:

6 0
1 year ago
Read 2 more answers
If tu = 6 units, what must be true? su + ut = rt rt + tu = rs rs + su = ru tu + us = rs
Ivan

Answer:

Explanation:

If TU=6 then SU+UT= RT

5 0
2 years ago
A group of campers walked at a speed of 4. 5 mph from their campsite to a rest area. Their return trip to the campsite took 15 m
tia_tia [17]

The distance between the campsite and the rest area is 9 miles.

The given parameters:

  • <em>Initial speed of the campers, u = 4.5 mph</em>
  • <em>Final speed of the campers, v = 4 mph</em>

<em />

Let the time of motion from the campsite to rest area = t (hours)

Time for return trip = t hours +  15 mins

                               = (t + 0.25) hours

Let the distance between the campsite and rest area = d

d = 4.5t

d = 4(t + 0.25)

4.5t = 4(t + 0.25)

4.5t = 4t + 1

4.5t - 4t = 1

0.5t = 1

t = 2 hours

The distance between the campsite and the rest area is calculated as follows;

d = 4.5t

d = 4.5 x 2

d = 9 miles

Thus, the distance between the campsite and the rest area is 9 miles.

Learn more about distance and speed here: brainly.com/question/2854969

5 0
2 years ago
Hi please help with this science question but im just puting it for sat and also im in 6th grade and not the age it says
serg [7]

Answer:

D. Molten

Explanation:

3 0
3 years ago
Read 2 more answers
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