Find the sum of this problem.

46 is between two integers. Name the integers and state the integer that is closest. plz i need help

Reika [66]

Answer:

45 and 47

Step-by-step explanation:

3 0

3 years ago

Find the value of given expression<br><br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B2%20-%201%7D%20" id="TexFormula1" title

Bingel [31]

Answer:

Answer is 1 I hope this help

7 0

2 years ago

Read 2 more answers

P(x) = 2x² + 1<br> What is the inverse for p(x)?

Serhud [2]

Answer:

$P^{-1} (x)=\sqrt{\frac{x-1}{2} }$

Step-by-step explanation:

1. $P(x)=2x^{2} +1$

2. $y=2x^{2} +1$

3. $x=2y^{2} +1$

4. $2y^{2} =x-1$

5. $y^{2} =\frac{x-1}{2}$

6. $y=\sqrt{\frac{x-1}{2} }$

7. $P^{-1} (x)=\sqrt{\frac{x-1}{2} }$

4 0

3 years ago

What’s the volume of a rectangle solid with the given dimensions: length 20, width 23, height 26

ANEK [815]

The volume of the rectangular solid is: 11,960 units³.

<h3>How to Find the Volume of a Rectangular Solid?</h3>

The formula to find the volume of a rectangular solid is: (length)(width)(height).

Given the dimensions as:

Length = 20 units
Width = 23 units
Height = 26 units

Volume = (20)(23)(26)

Volume of the rectangular solid = 11,960 units³.

Learn more about about the volume of rectangular solid on:

brainly.com/question/15116803

#SPJ1

8 0

1 year ago

Consider the linear transformation T from V = P2 to W = P2 given by T(a0 + a1t + a2t2) = (2a0 + 3a1 + 3a2) + (6a0 + 4a1 + 4a2)t

Svet_ta [14]

Answer:

$[T]EE=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]$

Step-by-step explanation:

First we start by finding the dimension of the matrix [T]EE

The dimension is : Dim (W) x Dim (V) = 3 x 3

Because the dimension of P2 is the number of vectors in any basis of P2 and that number is 3

Then, we are looking for a 3 x 3 matrix.

To find [T]EE we must transform the vectors of the basis E and then that result express it in terms of basis E using coordinates and putting them into columns. The order in which we transform the vectors of basis E is very important.

The first vector of basis E is e1(t) = 1

We calculate T[e1(t)] = T(1)

In the equation : 1 = a0

$T(1)=(2.1+3.0+3.0)+(6.1+4.0+4.0)t+(-2.1+3.0+4.0)t^{2}=2+6t-2t^{2}$

$[T(e1)]E=\left[\begin{array}{c}2&6&-2\\\end{array}\right]$

And that is the first column of [T]EE

The second vector of basis E is e2(t) = t

We calculate T[e2(t)] = T(t)

in the equation : 1 = a1

$T(t)=(2.0+3.1+3.0)+(6.0+4.1+4.0)t+(-2.0+3.1+4.0)t^{2}=3+4t+3t^{2}$

$[T(e2)]E=\left[\begin{array}{c}3&4&3\\\end{array}\right]$

Finally, the third vector of basis E is $e3(t)=t^{2}$

$T[e3(t)]=T(t^{2})$

in the equation : a2 = 1

$T(t^{2})=(2.0+3.0+3.1)+(6.0+4.0+4.1)t+(-2.0+3.0+4.1)t^{2}=3+4t+4t^{2}$

Then

$[T(t^{2})]E=\left[\begin{array}{c}3&4&4\\\end{array}\right]$

And that is the third column of [T]EE

Let's write our matrix

$[T]EE=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]$

T(X) = AX

Where T(X) is to apply the transformation T to a vector of P2,A is the matrix [T]EE and X is the vector of coordinates in basis E of a vector from P2

For example, if X is the vector of coordinates from e1(t) = 1

$X=\left[\begin{array}{c}1&0&0\\\end{array}\right]$

$AX=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]\left[\begin{array}{c}1&0&0\\\end{array}\right]=\left[\begin{array}{c}2&6&-2\\\end{array}\right]$

Applying the coordinates 2,6 and -2 to the basis E we obtain

$2+6t-2t^{2}$

That was the original result of T[e1(t)]

8 0

3 years ago