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natita [175]
3 years ago
7

Lilly has 38 baseballs. She places all the baseballs into one or more containers. Lilly places the same number of baseballs into

each container. How many possible ways can the baseballs be placed into containers?
Mathematics
2 answers:
ankoles [38]3 years ago
8 0
There are 4 ways she can place it
Dvinal [7]3 years ago
7 0

Answer:

There are 4 possible ways to place the baseballs into containers.

Step-by-step explanation:

please mark me as brainliest

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The mass of a grain of sand is about 103 gram.
KatRina [158]

1 grain = 103g

2kg = 2000g

grains = 2000g/103g = 19.417

Answer:

About 19.417 grains

3 0
4 years ago
The graph of f(x)=x2 was transformed to create the graph of g(x)=(x+5)2.
alexandr1967 [171]

Answer:

a horizontal shift left

Step-by-step explanation:

my teacher always tells me whatever you think it is in the parenthisis do the opposite. Sorry not a good explanation

5 0
3 years ago
Determine 7th term in the geometric sequence whose first term is 5 and whose common ratio is 2.
Sedbober [7]

Answer: 320

<u>Step-by-step explanation:</u>

a_n=a_1(r)^{n-1}\quad \text{where}\ a_1\ \text{is the first term, r is the ratio, n is the term}

a_7=5(2)^{7-1}

   =5(2)^{6}

   =5(64)}

   =320

8 0
3 years ago
Read 2 more answers
Someone help and please make sure the answer is right! :)
TEA [102]

Answer:

84

Step-by-step explanation:

180-51-45=84

I think this would be the answer since triangles add up to be 84 and we are just finding the last missing angle.

hope this helps :)

8 0
3 years ago
Read 2 more answers
If cot theta = -2, find the value of cot theta + cot (theta -pi) + cot (theta-2pi)
nika2105 [10]

Given:

\cot \theta = -2

To find:

The value of \cot \theta +\cot (\theta -\pi)+\cot(\theta -2\pi).

Solution:

We know that,

\cot (\theta -n\pi)=\cot \theta         ...(i)

Where n is an integer.

We have,

\cot \theta +\cot (\theta -\pi)+\cot(\theta -2\pi)

Using (i), it can be written as

\cot \theta +\cot (\theta -\pi)+\cot(\theta -2\pi)=\cot \theta +\cot \theta +\cot \theta

\cot \theta +\cot (\theta -\pi)+\cot(\theta -2\pi)=3\cot \theta

It is given that \cot \theta = -2.

\cot \theta +\cot (\theta -\pi)+\cot(\theta -2\pi)=3(-2)

\cot \theta +\cot (\theta -\pi)+\cot(\theta -2\pi)=-6

Therefore, the value of the given function expression is -6.

6 0
3 years ago
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