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mote1985 [20]
4 years ago
7

Find all points having an x-coordinate of 4 whose distance from the point (-2,-1) is 10

Mathematics
1 answer:
irina1246 [14]4 years ago
8 0
d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\
10=\sqrt{(4-(-2))^2+(y-(-1))^2}\\
10=\sqrt{6^2+(y+1)^2}\\
10=\sqrt{36+y^2+2y+1}\\
10=\sqrt{y^2+2y+37}\\
100=y^2+2y+37\\
y^2+2y-63=0\\
y^2+9y-7y-63=0\\
y(y+9)-7(y+9)=0\\
(y-7)(y+9)=0\\
y=7 \vee y=-9\\\\
\boxed{(x,y)=\{(4,-9),(4,7)\}}


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3 years ago
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Can someone tell me if i did this right? im also not sure which one is the scale factor.
PIT_PIT [208]
If you are moving the center of circle 2 to the the center of circle 1, then the translation rule is (x,y) ---> (x+4, y+10). 
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Also, y = -2 turns into y = 8. We add 10

The scale factor to turn the radius r = 4 into r = 8 is 2. Basically we double the radius. We can divide the two radii to see 8/4 = 2

----------------------------------

Summary:
To go from circle 2 to circle 1, we apply these two transformations
translation: (x,y) ---> (x+4, y+10)
dilation: scale factor 2

note: 
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katrin2010 [14]

Answer:

48 hats and 104 shirts

Step-by-step explanation:

These are the equations you build from the problem:

h + s = 152

8.50h + 12s = 1656

This is how I solved them:

s= 152-h

8.5h + 12(152-h) = 1656

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Solve for h

h= 48

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3 years ago
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