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DENIUS [597]
2 years ago
6

Convert fractions to a fraction out of 100. 15/60=? 30/60=? 25/75=?

Mathematics
1 answer:
goblinko [34]2 years ago
8 0
<h3>Answer:</h3>
  • 25/100
  • 50/100
  • (33 1/3)/100
<h3>Step-by-step explanation:</h3>

The numerator can be found by multiplying each of these fractions by 100. It can be helpful to reduce these fractions first.

Here, we calculate those numerators.

a) 15/60 · 100 = 1/4 · 100 = 100/4 = 25

b) 30/60 · 100 = 1/2 · 100 = 100/2 = 50

c) 25/75 · 100 = 1/3 · 100 = 100/3 = 33 1/3

Of course, the denominator is 100, so the fractions are ...

... 15/60 = 25/100

... 30/60 = 50/100

... 25/75 = (33 1/3)/100

_____

<em>Comment on this solution</em>

Effectively, we have multiplied each fraction by 1 = 100/100. That is ...

... fraction × (100/100) = (fraction × 100)/100

This changes the form, but not the value.

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10

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3 years ago
A cone has a slant length of 10 and a diameter of 8. Height is unknown.
patriot [66]

Answer: 153.56

Step-by-step explanation:

Hi, to answer this question we have to apply the next formulas:

Volume of a cone: 1/3 π r² h

Where r is the radius and h is the height (unknown)

Diameter = r x 2

8 = 2r

8/2 =r

r = 4  

Before calculating the volume we have to apply the Pythagorean Theorem to find h. (where the slant is the hypotenuse and h and r are the sides of the triangle)

10 ² = h² + 4²

Solving for h

100 = h² + 16

100-16 = h²

84= h²  

√84 =h

9.16= h

Back on the volume formula:

V= 1/3 π r² h

V =1/3 π 4² (9.16) =153.56

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3 years ago
Weinstein, McDermott, and Roediger report that students who were givne questions to be answered while studying new material had
emmainna [20.7K]
<h2>Answer with explanation:</h2>

Let \mu be the population mean.

By considering the given information , we have

Null hypothesis : H_0: \mu=73.4

Alternative hypothesis :  H_a: \mu>73.4

Since alternative hypothesis is right-tailed , so the test is a right-tailed test.

Given : Sample size : n=16 , which is a small sample , so we use t-test.

Sample mean: \overline{x}=78.3  ;

Standard deviation: s=8.4

Test statistic for population mean:

t=\dfrac{\overline{x}-\mu}{\dfrac{s}{\sqrt{n}}}

i.e. t=\dfrac{78.3-73.4}{\dfrac{8.4}{\sqrt{16}}}\approx2.333

Using the standard normal distribution table of t , we have

Critical value for \alpha=0.01 : t_{(n-1,\alpha)}=t_{(15,0.01)}=2.602

Since , the absolute value of t (2.333) is smaller than the critical value of t (2.602) , it means we do not have sufficient evidence to reject the null hypothesis.

Hence, we conclude that we do not have enough evidence to support the claim that answering questions while studying produce significantly higher exam scores.

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