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Jobisdone [24]
2 years ago
9

A 300 ft long wire is used to fence a rectangular plot whose length is twice its width. Find the area

Mathematics
2 answers:
Neko [114]2 years ago
6 0

Answer:

5000m^2

Step-by-step explanation:

width = w

length = 2w

perimeter: 2(w) + 2(2w) = 300

2w + 4w = 300

6w = 300

width = w = 50

width*2 = length

length = l = 100

Hence,

Length =  2w = 100 m

Width = w = 50 m

Area = l*w = 100*50 = 5000m^2

Yuri [45]2 years ago
3 0

Answer:

<em>5,000 square feet</em>

<u>Skills Needed: 2-D Geometry</u>

Step-by-step explanation:

1) First, it says that 300 ft is the total amount of wire used to build the rectangular plot. This means that 300 is the perimeter of the plot. It is the length of the entire boundary of the shape.

---> The formula for perimeter is: 2(l+w) for a rectangle.

2) We can use the perimeter formula to the find the length and width, and then use the area formula to find the area. Area is the total amount of space taken up by the figure in 2 dimensions.

---> Area formula is: l*w for a rectangle

3) We are given that the length is 2 times as much as (or twice as much as) the width.

---> l=2w

Using perimeter formula:

2(l+w) = 300 \\ 2(2w+w) = 300 \\ 2(3w) = 300 \\ 6w = 300\\ w = 50

We substitute in for length and then solve for width as shown above.

Given the width, we can solve for length using the fact that length is twice the width.  

l=2w \\ l=2*50 \\ l=100

We use substitution to solve for length.

4) Now given length is 100, and with is 50, we can use the area formula.

A = l*w=100*50=5000

This means the area is 5000 square feet.

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Hello here is a solution : 

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3 years ago
Jeannine needs to decide what size to make a rectangular
Harlamova29_29 [7]

Answer:

Total number of possible combinations are 6

Length   width

23 dm     2m

21 dm       4 dm

19 dm       6 dm

17 dm         8 dm

15 dm         10 dm

13 dm          12 dm

Step-by-step explanation:

We are given that

Perimeter of rectangular garden=50 dm

Width is  even number.

Length is always longer than or equal to width.

Let length of rectangular garden=x

Width of  rectangular garden=y

We have to find the possible  number of combinations .

Perimeter of rectangular garden=2(x+y)

2(x+y)=50

x+y=50/2

x+y=25

If y=2 dm

x=25-2=23 dm

If y=4 dm

x=25-4=21 dm

If y=6 dm

x=25-6=19 dm

If y=8 dm

x=25-8=17 dm

If y=10 dm

x=25-10=15 dm

If y=12 dm

x=25-12=13 dm

If y=14 dm

x=25-14=11 dm

x<y

It is  not possible

Then, possible combinations are 6

Length   width

23 dm     2m

21 dm       4 dm

19 dm       6 dm

17 dm         8 dm

15 dm         10 dm

13 dm          12 dm

5 0
3 years ago
If anyone can i help me
natulia [17]

Answer:

x=9.4

x=9.43

Step-by-step explanation:

I used the Pythagorean theorem.

Have a nice day!

and can I maybe have brainliest? Thanks!

3 0
3 years ago
Read 2 more answers
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