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olga55 [171]
2 years ago
12

Qaudriladrial ABCD had cordinates A (3, 5) B(5, 2) C(8, 4) D(6, 7) qaudriladrial ABCD is a what?

Mathematics
1 answer:
Lorico [155]2 years ago
8 0

The quadrilateral is a square

<h3>What are quadrilaterals?</h3>

Quadrilaterals are polygons, that have four sides and four corners

The coordinates are given as:

  • A = (3, 5)
  • B = (5, 2)
  • C = (8, 4)
  • D = (6, 7)

Start by calculating the adjacent side lengths using:

d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

So, we have:

AB = \sqrt{(3- 5)^2 + (5- 2)^2}

AB = \sqrt{13}

BC = \sqrt{(8- 5)^2 + (4- 2)^2}

BC = \sqrt{13}

The side lengths are equal.

Hence, the quadrilateral is a square

Read more about quadrilaterals at:

brainly.com/question/5715879

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Answer:

Three (3) is the correct answer

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3 years ago
A pole-vaulter uses a 15-foot-long pile. She grips the pole so that the segment below her left hand is twice the length of the s
Shalnov [3]
Let x + 1.5 be length of segment above left hand
Let 2x be length of segment below left hand

15 = x + 1.5 + 2x
15 = 3x + 1.5
15 - 1.5 = 3x
13.5 = 3x
13.5/3= 3x/3 
4.5 = x
x = 4.5
This is the length above the left hand. 

2x must be then 4.5*2 = 9 foot
This is the length below the left hand. 

Checking
4.5 + 9 + 1.5 = 15 foot 

Adding length below left hand & length of left hand to right hand:
9 + 1.5 = 10.5
The right hand is hence 10.5 foot far up the pole.
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3 years ago
Which inequalities have -0.5, 2.5, and 4 as part of the solution set? Select all that apply.
omeli [17]

Answer:

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sammy [17]
Alright,

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Simplify by expressing fractional exponents instead of radicals
igomit [66]

Answer:

a^{\frac{1}{2}}b^{\frac{1}{2}}

Step-by-step explanation:

Given:

The expression in radical form is given as:

\sqrt{ab}

We need to express this in fractional exponent form.

We know that,

\sqrt a=a^{\frac{1}{2}}

Also, \sqrt{ab}=\sqrt a\times \sqrt b

Now, clubbing both the properties of square root function, we can rewrite the given expression as:

\sqrt{ab}=\sqrt a \times \sqrt b\\\\\sqrt{ab}=a^{\frac{1}{2}}\times b^{\frac{1}{2}}\\\\\therefore \sqrt{ab}=a^{\frac{1}{2}}b^{\frac{1}{2}}

So, the given expression in fractional exponents form is a^{\frac{1}{2}}b^{\frac{1}{2}}.

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