Qaudriladrial ABCD had cordinates A (3, 5) B(5, 2) C(8, 4) D(6, 7) qaudriladrial ABCD is a what?

Mathematics

1 answer:

Lorico [155]2 years ago

8 0

The quadrilateral is a square

<h3>What are quadrilaterals?</h3>

Quadrilaterals are polygons, that have four sides and four corners

The coordinates are given as:

A = (3, 5)
B = (5, 2)
C = (8, 4)
D = (6, 7)

Start by calculating the adjacent side lengths using:

$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

So, we have:

$AB = \sqrt{(3- 5)^2 + (5- 2)^2}$

$AB = \sqrt{13}$

$BC = \sqrt{(8- 5)^2 + (4- 2)^2}$

$BC = \sqrt{13}$

The side lengths are equal.

Hence, the quadrilateral is a square

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asambeis [7]

So the diagonal of cube
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remember that this is a 45,45 triangle so therefor
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28=x√2
divide both sides by √2
28/(√2)=x
the diagonal on the floor is 28/(√2)
the sides of the triangle form another 45 45 90 triangle with 28/(√2) as hyponuse so
a=b=x
c=x√2=28/(√2)
solve for x
x√2=28/(√2)
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same as mujlitply both sides by 1/(√2) so
28/(√2) times 1/(√2)=28/(2)=14
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the answer is 14cm