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dalvyx [7]
2 years ago
13

Sequence of transformation that take the graph y=x^2 to y=-2(x-5)^2+4

Mathematics
1 answer:
Lisa [10]2 years ago
3 0

Answer:

(x-5) so translated 5 units to the right

Multiplied with 2, p vertically compressed

+4 means translated 4 units up

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Please help stuck on probelem
Maurinko [17]
<h3>Answer:  36 square units</h3>

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Explanation:

Draw a horizontal line to cut the figure into a rectangle on top and a triangle down below.

The rectangle has length and width of 6 and 4 (horizontal and vertical components respectively). The area of this rectangle is 6*4 = 24 square units.

The triangle has a base of 6 and a height of 4. The base and height of any triangle are always perpendicular.

The area of the triangle is base*height/2 = 6*4/2 = 24/2 = 12 square units. If you were to cut out half of the triangle and rearrange things, you'll find that a rectangle can be formed. This rectangle is half in area that of the first rectangle we found. This is why we divide by 2 when finding the area of the triangle.

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3 years ago
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Riley has collected surveys for her final thesis project. One one question, 46.1% of respondents said that conditions were impro
ira [324]

Answer:

The maximum value of the confidence interval for this set of survey results is 51.73%.

Step-by-step explanation:

A confidence interval has two bounds, a lower bound and an upper bound.

These bounds depend on the sample proportion and on the margin of error.

The lower bound is the sample proportion subtracted by the margin of error.

The upper bound is the margin of error added to the sample proportion.

In this question:

Sample proportion: 46.1%

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3 years ago
Suppose r(t)=costi+sintj+3tk represents the position of a particle on a helix, where z is the height of the particle above the g
Ilia_Sergeevich [38]

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\vec v\left(\dfrac{16}3\right)=-\sin\dfrac{16}3\,\vec\imath+\cos\dfrac{16}3\,\vec\jmath+3\,\vec k

c. The tangent to \vec r(t) at t=\frac{16}3 is

\vec T(t)=\vec r\left(\dfrac{16}3\right)+\vec v\left(\dfrac{16}3\right)t

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2 years ago
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Answer:

ya i dont either

Step-by-step explanation:

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