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3 years ago

Sequence of transformation that take the graph y=x^2 to y=-2(x-5)^2+4

Mathematics

1 answer:

Lisa [10]3 years ago

3 0

Answer:

(x-5) so translated 5 units to the right

Multiplied with 2, p vertically compressed

+4 means translated 4 units up

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Tara has two bags of marbles. the first bag contains 6 red marbles, 5 blue marbles and 4 green marbles. the second bag contains

Alina [70]

Answer:

From the first bag the probability is 5 out of 15 or 1/3 simplified

The second bags probability is 4 out of 9

All the bags combined the probability is 9 out of 24

Step-by-step explanation:

The probability should be set up by putting the blue marbles as the numerator and the sum of all the marbles combined for the denominator

With everything said all you have to do is figure out the two steps an you’re good to go

7 0

3 years ago

Sally went to the clearance rack at a department store and found a shirt she wanted to buy. The shirt was $36.00 and is on sale

jeka57 [31]

Answer:

33.34%.

Step-by-step explanation:

Given that,

The actual price of the shirt = $36

Price on sale = $24

We need to find the percent of the decrease. The formula for the percentage is given by :

$\%=\dfrac{|\text{actual value-estimated value}|}{\text{actual value}}\times 100$

Putting all the values,

$\%=\dfrac{24-36}{36}\times 100\\\\=33.34\%$

So, the percentage decrease in the price of the shirt is 33.34%.

6 0

3 years ago

Math question down below

kolbaska11 [484]

Answer:

314.961

Step-by-step explanation:

3 0

3 years ago

Solve the equation.

Elanso [62]

Answer:

A, a= 87

Step-by-step explanation:

a+36=123

Step 1: Subtract 36 from both sides.

a+36−36=123−36

a=87

Hope this helps!

4 0

3 years ago

Read 2 more answers

The value of a boat if depreciating at at a rate of 9% per year. In 2006 the boat was worth $17,800. Find the worth of the boat

svetlana [45]

Answer:

The worth of boat in 2013 will be $9202.6

Step-by-step explanation:

Rate of depreciation = 9% = 0.09

Cost of Boat in 2006 =$ 17,800

Cost of Boat in 2013 = ?

Years = 2013-2006= 7 years

The formula used is: $\mathbf{A=P(1+r)^{t}}$

Since the value of boat is depreciating the value of r will be r=-0.09

Here P = 17,800 , r=-0.09 and t = 7 years Finding A

$A=P(1+r)^{t}\\A=17,800(1+(-0.09))^7\\A=17,800(0.91)^7\\A=17,800(0.517)\\A=9202.6$

So, the worth of boat in 2013 will be $9202.6

4 0

3 years ago