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goldenfox [79]
4 years ago
10

What is the midpoint of the x-intercepts of f(x) = (x – 4)(x + 4)?

Mathematics
2 answers:
ra1l [238]4 years ago
5 0
Since the x intercepts are when f(x)=0, they're at x=4 and x=-4 due to that 4-4=0 and -4+4=0 and anything times 0 is 0. Next, to find the midpoint, we add the numbers and divide by 2, getting (-4-(-4))/2=0/2=0 for our x value, and since f(x)=y and that's 0 since it's a x intercept, we have (0,0)
atroni [7]4 years ago
4 0

Answer:

midpoint is (0,0)

Step-by-step explanation:

the midpoint of the x-intercepts of

f(x) = (x - 4)(x + 4)

To find the midpoint of x intercepts, we need to find the x intercepts first

we find x intercepts by replacing f(x) with 0

0 = (x - 4)(x + 4)

Set each factor =0 and solve for x

x-4=0 , x=4

x+4=0, x=-4

X intercepts are -4  and 4

Midpoint of -4 and 4 is \frac{-4+4}{2} =0

X intercepts lies on x axis . So midpoint is (0,0)

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4 years ago
The cost of riding in a cab is $3.00 plus $0.75 per mile. The equation that represents this relation is y = 0.75x +3, where x is
Gemiola [76]

Answer:

Yes, the relation is a function.

Step-by-step explanation:

Given:

The equation that represents the cost of riding a cab is given as:

y=0.75x+3

Where, 'x' is the number of miles traveled and 'y' is the the total cost of the trip.

The above equation represents a line as it is of the form y=mx+b which represents a line with constant slope.

Now, in order to plot this equation, we need at least two points.

Now, let x =0, then

y=0.75(0)+3=3. So, (0, 3) is a point on the line.

Let x =1, then

y=0.75(1)+3=3.75. So, (1, 3.75) is a point on the line.

Plot these two points on a graph and draw a line passing through these two points.

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8 0
3 years ago
A train leaves San Diego at 1:00 pm. A second train leaves the same city in the same direction at 3:00 pm. The second train trav
Soloha48 [4]

Answer:

The speed of the first train is 45 mph and the speed of the second train is 75 mph

Step-by-step explanation:

Let x represent the speed of the first train in mph. Since the second train, is 30 mph faster then the first, therefore the speed of the second train is (x + 30).

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3x + 90 = 5x

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Therefore the speed of the first train is 45 mph and the speed of the second train is 75 mph (45 mph + 30 mph).

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