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goldenfox [79]
3 years ago
10

What is the midpoint of the x-intercepts of f(x) = (x – 4)(x + 4)?

Mathematics
2 answers:
ra1l [238]3 years ago
5 0
Since the x intercepts are when f(x)=0, they're at x=4 and x=-4 due to that 4-4=0 and -4+4=0 and anything times 0 is 0. Next, to find the midpoint, we add the numbers and divide by 2, getting (-4-(-4))/2=0/2=0 for our x value, and since f(x)=y and that's 0 since it's a x intercept, we have (0,0)
atroni [7]3 years ago
4 0

Answer:

midpoint is (0,0)

Step-by-step explanation:

the midpoint of the x-intercepts of

f(x) = (x - 4)(x + 4)

To find the midpoint of x intercepts, we need to find the x intercepts first

we find x intercepts by replacing f(x) with 0

0 = (x - 4)(x + 4)

Set each factor =0 and solve for x

x-4=0 , x=4

x+4=0, x=-4

X intercepts are -4  and 4

Midpoint of -4 and 4 is \frac{-4+4}{2} =0

X intercepts lies on x axis . So midpoint is (0,0)

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If the angles of a triangle are (2y - 5)degrees, (y + 20)degrees, and (3y-5) degrees what are the values of the angles​
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Answer:

<h3>\boxed{ \boxed{ \bold{ \sf{51.68  \: , \: 48.34 \:,  \: 80.02}}}}</h3>

Step-by-step explanation:

Let's solve:

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\sf{2y - 5 + y + 20 + 3y - 5 = 180}

Collect like terms

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Move constant to right hand side and change it's sign

⇒\sf{6y = 180 - 10}

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Divide both sides of the equation by 6

⇒\sf{ \frac{6y}{6}  =  \frac{170}{6} }

Calculate

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