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Igoryamba
2 years ago
5

If the distance between A(0, 4) and B(3,a) is 5 units then find the value of a.​

Mathematics
2 answers:
Anna007 [38]2 years ago
4 0

Answer:

Step-by-step explanation:

a = 0

So that AOB makes a right triangle with sides 3-4-5

Phoenix [80]2 years ago
4 0

Answer:

a = 8

Step-by-step explanation:

Calculate AB using the distance formula and equate to 5

d = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2    }

with (x₁, y₁ ) = A (0, 4 ) and (x₂, y₂ ) = B (3, a )

d = \sqrt{(3-0)^2+(a-4)^2}

  = \sqrt{3^2+(a-4)^2}

  = \sqrt{9+(a-4)^2} , then

\sqrt{9+(a-4)^2} = 5 ( square both sides )

9 + (a - 4)² = 5² = 25 ( subtract 9 from both sides )

(a - 4)² = 16 ( take square root of both sides )

a - 4 = 4 ( add 4 to both sides )

a = 8

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8 0
3 years ago
Find the solutions to x2 = 12
nasty-shy [4]

Answer:

x = ± 2\sqrt{3}

Step-by-step explanation:

Given

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4 years ago
A tree is 4 m 25 cm high! A pole is 70 cm shorter. How high is the pole? ​
ivanzaharov [21]

-------------------------------------------------------------------------------------------------------------

Answer:  \textsf{3955cm}

-------------------------------------------------------------------------------------------------------------

Given: \textsf{Tree = 4m and 25cm, Pole = 70cm shorter}

Find: \textsf{The height of the pole}

Solution: The first step that we must take is to convert the tree height to centimeters and after doing so we would just subtract 70 cm from that to get the pole height.

<u>Convert to cm</u>

  • \textsf{m = 1000cm}
  • \textsf{4m = (1000cm * 4)}
  • \textsf{4m = 4000cm}

<u>Combine</u>

  • \textsf{4000cm + 25cm}
  • \textsf{4025cm}

<u>Subtract 70 from the tree height</u>

  • \textsf{4025cm - 70cm}
  • \textsf{3955cm}

Using the information from the problem the height of the pole would be 3955cm.

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Search it up on google
3 0
3 years ago
12.915 to 2 decimal places
snow_tiger [21]

Answer:

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Step-by-step explanation:

rounding the 1 hundredth up to 2 because of the 5 thousandth

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