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Xelga [282]
3 years ago
10

Which values of a, b, and c correctly complete the division?

Mathematics
2 answers:
Rashid [163]3 years ago
7 0
Last one is correct.
1/4 divide 5/6 = 1/4 x 6/5 (flip the fraction upside down to multiply the fraction)
Dmitriy789 [7]3 years ago
5 0

Answer:

a=4,b=6,c=5

Step-by-step explanation:

Recall that to divide fractions, you take the dividend and multiply it by the divisor's reciprocal, therefore:

\frac{1}{4}\div\frac{5}{6}=\frac{1}{4}*\frac{6}{5}=\frac{6}{20}=\frac{3}{10}

It's easy to see now that a=4,b=6,c=5.

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I got shocked when I entered my school bus last Thursday. It was full of lizards and snakes. There were 214 lizards and snakes o
s344n2d4d5 [400]

Answer:

x=lizards y=snakes

x+36=y x+y=214

x + x +36=214

2x=214-36

2x/2=178/2

x=89lizards y=89+36=125snakes

Step-by-step explanation:

f= female sankes m=male snakes

m+31=f

m+f=125

m+m+31=125

2m=125-31

2m/2=94/2

m=47 male snakes

f=47+31=78female snakes

7 0
3 years ago
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Help me for brainlist. please I really need it.
Andrej [43]

Answer:

1200..............................

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3 years ago
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Consider the graph below. Which of the following coordinates belong in the box?
AveGali [126]
I think it’s b my guess
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4 years ago
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Lizzie rolls two dice. What is the probability that the sum of the dice is:
zhenek [66]

Answer:

A.\ \dfrac{1}{3}\\B.\ \dfrac{5}{12}\\C.\ \dfrac{7}{36}\\

Step-by-step explanation:

Total outcomes possible: 36

A. Divisible by 3

Possible options are:

3, 6, 9 and 12.

Possible outcomes for 3 are: {(1,2), (2,1)} Count 2

Possible outcomes for 6 are: {(1,5), (2,4), (3,3), (5,1),(4,2)} Count 5

Possible outcomes for 9 are: {(3,6), (4,5), (5,4),(6,3)} Count 4

Possible outcomes for 12 are: {(6,6)} Count 1

Total count = 2 + 5 + 4 + 1 = 12

Probability of an event E can be formulated as:

P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}

P(A)  = \dfrac{12}{36} = \dfrac{1}{3}

B. Less than 7:

Possible sum can be 2, 3, 4, 5, 6

Possible cases for sum 2: {(1,1)}  Count 1

Possible cases for sum 3: {(1,2), (2,1)}  Count 2

Possible cases for sum 4: {(1,3), (3,1), (2,2)}  Count 3

Possible cases for sum 5: {(1,4), (2,3), (3,2),(4,1)}  Count 4

Possible cases for sum 6: {(1,5), (2,4), (3,3), (5,1),(4,2)} Count 5

Total count = 1 + 2 + 3 + 4 + 5 = 15

P(B)  = \dfrac{15}{36} = \dfrac{5}{12}

C. Divisible by 3 and less than 7:

P(A \cap B) = \dfrac{n(A\cap B)}{\text{Total Possible outcomes}}

Here, common cases are:

Possible outcomes for 3 are: {(1,2), (2,1)} Count 2

Possible outcomes for 6 are: {(1,5), (2,4), (3,3), (5,1),(4,2)} Count 5

P(A \cap B) = \dfrac{7}{\text{36}}

5 0
3 years ago
Type the correct answer in the box. Use numerals instead of words. If necessary, use / for the fraction bar.
Degger [83]

Answer:

So do you already have the answer? Also 1/20 looks right.

Step-by-step explanation:

8 0
4 years ago
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