Which values of a, b, and c correctly complete the division?

Mathematics

2 answers:

Rashid [163]2 years ago

7 0

Last one is correct.
1/4 divide 5/6 = 1/4 x 6/5 (flip the fraction upside down to multiply the fraction)

Dmitriy789 [7]2 years ago

5 0

Answer:

$a=4,b=6,c=5$

Step-by-step explanation:

Recall that to divide fractions, you take the dividend and multiply it by the divisor's reciprocal, therefore:

$\frac{1}{4}\div\frac{5}{6}=\frac{1}{4}*\frac{6}{5}=\frac{6}{20}=\frac{3}{10}$

It's easy to see now that $a=4,b=6,c=5$ .

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Critical Thinking: Empirical/Quantitative Skills

aliya0001 [1]

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1. 0.0910 = 9.10% probability that exactly 180 passengers show up for the flight.

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Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .