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elena55 [62]
3 years ago
6

Please just give me the answer to this question, I’m so lazy haha the Pablo one thank you!

Mathematics
1 answer:
Artyom0805 [142]3 years ago
4 0

Answer:

I would say its 640 seconds sorry if I'm wrong

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If sinФ = 1/6 . what are the values of cosФ and tanФ? Show steps
Marianna [84]

sinФ = 1/6

sinФ = opposite/hypotenuse

cosФ = adjacent/hypotenuse

tanФ = opposite/adjacent

SOHCAHTOA

1^(2)+b^(2)=6^(2)

1+b^(2)=36

b^(2)=35

\sqrt{35}

cosФ = \sqrt{35}/6

tanФ = 1/\sqrt{35} = \sqrt{35}/35

8 0
3 years ago
Read 2 more answers
2
Fofino [41]

9514 1404 393

Answer:

  1.1.1  sin(241°) = -√t

  1.1.2  cos(61°) = √(1 -t)

Step-by-step explanation:

<u>Given</u>:

 sin(61°) = √t

<u>Find</u>:

  1.1.1  sin(241°)

  1.1.2  cos(61°)

<u>Solution</u>:

1.1.1  sin(180° +x) = -sin(x)

  sin(241°) = -sin(61°) = -√t

__

1.1.2  cos(x) = √(1-sin²(x))

  cos(61°) = √(1 -(√t)²) = √(1 -t)

4 0
3 years ago
Let h(x)=(g o f)(x)=√x+3 <br> Which of the following could be a possible decomposition of h(x)?
hodyreva [135]
In this case, h(x) = sqrt(x) + 3

A. f(x)=x+3; g(x)=√x 
B. f(x)=x; g(x)=x+3 
C. f(x)=√x; g(x)=x+3 
D. f(x)=3x; g(x)=√x

Again, you need to find a function f(x) that once evaluated in g(x) gives us h(x)

h(x) =  g(f(x))

Looking at the options, the answer is C.

g(f(x)) = f(x) + 3 = sqrt (x) + 3 = h(x)
8 0
4 years ago
Read 2 more answers
WILL MARK BRAINLYIST
rodikova [14]

Answer:

D = 45 and C = 26

Step-by-step explanation:

The bigger triangle has a 90 degree corner add that to 64 and you will get 164 (all of the triangles angles have to add to 180) from 180 subtract 164 and you get 26 which is C's answer

For D just divide 90 by 2 (90/2)=45

7 0
3 years ago
PLEASE HELP! GIVING BRAINLIEST! DUE SOON PLEASE HELP!
Mrrafil [7]

Answer:

4-9 = 4+(-9)

-6-7 = -6+(-7)

-4-(-9) = -4 + 9

6-(-7) = 6+7

Step-by-step explanation:

Double negatives means a positive and one positive and one negative is a negative.

Please give brainliest. I am working hard to get it.

7 0
2 years ago
Read 2 more answers
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