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2 years ago

Please help me asap.

Mathematics

1 answer:

Finger [1]2 years ago

8 0

Answer:

30.2 aka C

Step-by-step explanation:

The formula for the area of a circle is A = pir^2. Knowing this we can create the equation A = 3.14(3.1)^2. Following PEMDAS square 3.1 to get 9.61. Then you multiply 9.61 with 3.14 to get 30.1754. When you round to the nearest tenth you get 30.2.

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3 years ago

8.52 The heights of 2-year-old children are normally distributed with a mean of 32 inches and a standard deviation of 1.5 inches

sweet [91]

Answer:

Heights of 29.5 and below could be a problem.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The heights of 2-year-old children are normally distributed with a mean of 32 inches and a standard deviation of 1.5 inches.

This means that $\mu = 32, \sigma = 1.5$

There may be a problem when a child is in the top or bottom 5% of heights. Determine the heights of 2-year-old children that could be a problem.

Heights at the 5th percentile and below. The 5th percentile is X when Z has a p-value of 0.05, so X when Z = -1.645. Thus

$Z = \frac{X - \mu}{\sigma}$

$-1.645 = \frac{X - 32}{1.5}$

$X - 32 = -1.645*1.5$

$X = 29.5$

Heights of 29.5 and below could be a problem.

4 0

2 years ago

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Vesna [10]

Ascending order= 6, 8, 12, 12, 12, 16

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Mode = Most number of observations= 12

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

Please help me asap.​

Please help me asap.