The weight that can be safely supported by a 2- by6-inch support beam varies inversely with its length. A builder finds that a
support beam that is 6 feet long will support 800 pounds. Find the weight that can be safely supported by a beam that is 16 feet long.
1 answer:
800/6=x/16 6x=12800 divide and get 2133 1/3
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The third answer option is correct. sqrt(x) = x^(1/2). So sqrt(121) = 121^(1/2).
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