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stich3 [128]
3 years ago
14

The weight that can be safely supported by a​ 2- by​6-inch support beam varies inversely with its length. A builder finds that a

support beam that is 6 feet long will support 800 pounds. Find the weight that can be safely supported by a beam that is 16 feet long.
Mathematics
1 answer:
maw [93]3 years ago
7 0
800/6=x/16         6x=12800          divide and get 2133   1/3
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<img src="https://tex.z-dn.net/?f=%28x%5E%7B2%7D%20%2Bx-3%29%3A%20%28x%5E%7B2%7D%20-4%29%5Cgeq%201" id="TexFormula1" title="(x^{
Jlenok [28]

Answer:

x>2

Step-by-step explanation:

When given the following inequality;

(x^2+x-3):(x^2-4)\geq1

Rewrite in a fractional form so that it is easier to work with. Remember, a ratio is another way of expressing a fraction where the first term is the numerator (value over the fraction) and the second is the denominator(value under the fraction);

\frac{x^2+x-3}{x^2-4}\geq1

Now bring all of the terms to one side so that the other side is just a zero, use the idea of inverse operations to achieve this:

\frac{x^2+x-3}{x^2-4}-1\geq0

Convert the (1) to have the like denominator as the other term on the left side. Keep in mind, any term over itself is equal to (1);

\frac{x^2+x-3}{x^2-4}-\frac{x^2-4}{x^2-4}\geq0

Perform the operation on the other side distribute the negative sign and combine like terms;

\frac{(x^2+x-3)-(x^2-4)}{x^2-4}\geq0\\\\\frac{x^2+x-3-x^2+4}{x^2-4}\geq0\\\\\frac{x+1}{x^2-4}\geq0

Factor the equation so that one can find the intervales where the inequality is true;

\frac{x+1}{(x-2)(x+2)}\geq0

Solve to find the intervales when the equation is true. These intervales are the spaces between the zeros. The zeros of the inequality can be found using the zero product property (which states that any number times zero equals zero), these zeros are as follows;

-1, 2, -2

Therefore the intervales are the following, remember, the denominator cannot be zero, therefore some zeros are not included in the domain

x\leq-2\\-2

Substitute a value in these intervales to find out if the inequality is positive or negative, if it is positive then the interval is a solution, if it is negative then it is not a solution. This is because the inequality is greater than or equal to zero;

x\leq-2   -> negative

-2   -> neagtive

-1\leq x   -> neagtive

x>2   -> positive

Therefore, the solution to the inequality is the following;

x>2

6 0
3 years ago
Please help me now!!!!!!!!!!!
Thepotemich [5.8K]

Answer:

Calculate the slope in the four intervals.

m = (f(b) - f(a)) / (b - a) slope in Intervall [a; b]

m1 = (3 - 0) / (2 - 0) = 1.5

m2 = (11 - 3) / (4 - 2) = 4

m3 = (23 - 3) / (6 - 2) = 5

m4 = (23 - 11) / (6 - 4) = 6

between x = 4 and x = 6 is the correct answer.

3 0
3 years ago
Can someone please give me the (Answers) to this? ... please ...
Tpy6a [65]

Answer:

<em><u>If this is correct, can you mark me as Brainliest Please :)</u></em>

Step-by-step explanation:

  •  <em>Alternate Interior Angles : 2,7    3,6 </em>
  • <em>Corresponding Angles :  (7,5)(6,8)(3,1)(2’d)</em>
  • <em>Same- Side interior Angles:(6,7) (2,3)</em>
  • <em>Alternate Exterior Angles : (1,8) (5’d)</em>
  • Adjacent Angles : (3,7) (7,8)
  • Supplementary Angles:(1,2) (5,6)
  • Complementary Angles : (2,5) (1,6)
7 0
3 years ago
Please help with this
dimulka [17.4K]

Answer:

bruh

Step-by-step explanation:

4 0
3 years ago
What does 2.67+8.52 equal
Anon25 [30]

Answer:

11.19

Step-by-step explanation:

7 0
3 years ago
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