See picture for solution steps and answer.
<span>Round 38.872601 to the nearest hundredths place = </span>38.87
If it is (6^-4)^6 it should be 1/6^24. The picture was a bit blurry.
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Answer:
Step-by-step explanation:
Simplifying
2x(3 + 4a) = -16x + 6x
(3 * 2x + 4a * 2x) = -16x + 6x
Reorder the terms:
(8ax + 6x) = -16x + 6x
(8ax + 6x) = -16x + 6x
Combine like terms: -16x + 6x = -10x
8ax + 6x = -10x
Solving
8ax + 6x = -10x
Solving for variable 'a'.
Move all terms containing a to the left, all other terms to the right.
Add '-6x' to each side of the equation.
8ax + 6x + -6x = -10x + -6x
Combine like terms: 6x + -6x = 0
8ax + 0 = -10x + -6x
8ax = -10x + -6x
Combine like terms: -10x + -6x = -16x
8ax = -16x
Divide each side by '8x'.
a = -2
Simplifying
a = -2 <— answer
Just like at any other time, to add/subtract fractions you need a common denominator.
14)
1/(x^2+2x)+(x-1)/x=1 so we need a common denominator of x(x^2+2x)
[1(x)]/(x(x^2+2x))+[(x-1)(x^2+2x)]/(x(x^2+2x))=[1(x(x^2+2x))]/(x(x^2+2x))
now if you multiply both sides of the equation by x(x^2+2x) you are left with:
x+(x-1)(x^2+2x)=x(x^2+2x)
x+x^3+2x^2-x^2-2x=x^3+2x^2
x^3+x^2-x=x^3-2x^2
x^2-x=-2x^2
3x^2-x=0
x(3x-1)=0, x=0 is an extraneous solution as division by zero is undefined. So the only real solution is:
x=1/3
...
16)
(r+5)/(r^2-2r)-1=1/(r^2-2r) the common denominator we need r^2-2r so
[r+5-1(r^2-2r)]/(r^2-2r)=1/(r^2-2r), multiplying both sides by r^2-2r yields:
r+5-r^2+2r=1
-r^2+3r+5=1
-r^2+3r+4=0
r^2-3r-4=0
(r-4)(r+1)=0, r^2-2r cannot equal zero, r(r-2)=0, r cannot equal 0 or 2...
r=-1 or 4
