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melisa1 [442]
4 years ago
12

The midpoint between points (-3, 8) and (3, -4) is (0, y). What is y?​

Mathematics
1 answer:
Sonbull [250]4 years ago
5 0

The midpoint between points (-3, 8) and (3, -4) is (0, 2)

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An appliance company uses the function f
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4 years ago
What is the quotient 2y^-6y-20/4y+12 ÷ y+5y+6/3y^2+28y+27​
malfutka [58]

Answer with explanation:

 \rightarrow \frac{\frac{2y^2-6 y-20}{4 y+12}}{\frac{y^2+5 y+6}{3 y^2+28 y+27}}\\\\\rightarrow \frac{\frac{y^2-3y-10}{2 y+6}}{\frac{(y+2)(y+3)}{3 y^2+28 y+27}}\\\\\rightarrow \frac{\frac{(y-5)(y+2)}{2 (y+3)}}{\frac{(y+2)(y+3)}{3 y^2+28 y+27}}\\\\\rightarrow \frac{(y-5)(y+2)}{2 (y+3)}} \times {\frac{3 y^2+28 y+27}{(y+2)(y+3)}}\\\\ \rightarrow\frac{(y-5)\times(3 y^2+28 y+27)}{2 (y+3)^2}}

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=y×(y+3)+2×(y+3)

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→y² -3 y-10

=y² -5 y+2 y -10

=y×(y-5)+2×(y-5)

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6 0
3 years ago
Read 2 more answers
If the point (2, -10) lies on the graph of a direct variation, which represents the direct variation equation?
Zanzabum

\bf \qquad \qquad \textit{direct proportional variation} \\\\ \textit{\underline{y} varies directly with \underline{x}}\qquad \qquad y=kx\impliedby \begin{array}{llll} k=constant\ of\\ \qquad variation \end{array} \\\\[-0.35em] ~\dotfill\\\\ (\stackrel{x}{2},\stackrel{y}{-10})~~ \textit{we know } \begin{cases} x=2\\ y=-10 \end{cases}\implies -10=k2\implies \cfrac{-10}{2}=k\implies -5=k \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill y=-5x~\hfill

8 0
3 years ago
There are 5 children and 3 adults going on a trip.
sergij07 [2.7K]

Answer:

3/8

Step-by-step explanation:

8 0
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