3. Elena had 12 hours working at home daily as a full-time wife and mother. She

In the first region are located 6 Rattatta Pokemon hidden in the grass at any given time and 8 Pidgey Pokemon. What would be the

NikAS [45]

6+8= 14
6/14 is the probability

7 0

2 years ago

Missing some of the data points in the sample is a:

zepelin [54]

Answer:

Measurement error.

Step-by-step explanation:

Measurement Error are the error when there is difference found in true value of data and measured quantity of data. This difference could be found if we are missing some data in the sample.

The error could be reduced by carefully designing the process of data collection and it´s measurement.

Measurement error are classified into two type of error:

Random error.
Systematic error.

3 0

2 years ago

Exercise 1: In the right triangle below, calculate the measurement of the unknown side. Show your work.

vekshin1

Answer:

Exercise 1:

base [b]=8cm

perpendicular [p]=6cm

hypotenuse [h]=?

By using Pythagoras law

h²=p²+b²

h²=6²+8²

h=√100

h=10cm

So another side's length is 10cm

Exercise 2:

base [b]=6m

perpendicular [p]=bm

hypotenuse [h]=8m

By using Pythagoras law

h²=p²+b²

8²=b²+6²

b²=8²-6²

b=√28=2√7 0r 5.29 or 5.3

So height of kite is√28or 2√7 0r 5.29 or 5.3 m

Step-by-step explanation:

[Note: thanks for translating]

4 0

3 years ago

Ten years ago 53% of American families owned stocks or stock funds. Sample data collected by the Investment Company Institute in

Alborosie

Answer:

a) Null hypothesis: $p\geq 0.53$

Alternative hypothesis: $p < 0.53$

b) $z=\frac{0.46 -0.53}{\sqrt{\frac{0.53(1-0.53)}{300}}}=-2.429$

$p_v =P(Z$

c) So the p value obtained was a very low value and using the significance level given $\alpha=0.01$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of American families owning stocks or stock funds is significantly less than 0.53 .

Step-by-step explanation:

Data given and notation

n=300 represent the random sample taken

$\hat p=0.46$ estimated proportion of American families owning stocks or stock funds

$p_o=0.53$ is the value that we want to test

$\alpha=0.01$ represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

Part a

We need to conduct a hypothesis in order to test the claim that proportion is less than 0.53 or 53%.:

Null hypothesis: $p\geq 0.53$

Alternative hypothesis: $p < 0.53$

Part b

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.46 -0.53}{\sqrt{\frac{0.53(1-0.53)}{300}}}=-2.429$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.01$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(Z$

Part c

So the p value obtained was a very low value and using the significance level given $\alpha=0.01$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of American families owning stocks or stock funds is significantly less than 0.53 .

7 0

2 years ago

About 1.2 million people live in a region with a 6-mile radius what is the population destiny in people per square mile

Paladinen [302]

Answer:

10616 people per square mile

Step-by-step explanation:

No. of people living in the region = 1.2 million

Radius of the area = 6 mile

Since radius of region is given, area of can be calculated by using formula to get area of circle which is $\pi r^2$ where r is radius of circle.

the value of pie is 3.14 which will be used in the calculation

Area of region

$\pi r^2 \\=> 3.14 * 6^2\\=> 113.04$

population density of any place is calculated by dividing the total population of region with area of the region

mathematically it can be written as

population density of any place = the total population of region / area of the region

substituting the value of total population of region with 1.2 million and area of the region as calculated 113.04 square mile we have

population density of any place = 1.2 million/113.04 square mile

= 0.0106157113 million / square mile

Since one million is equal to 1,000,000

0.0106157113 million will be equal to 0.0106157113 * 1,000,000

= 10615.7113

rounding 10615.7113 nearest to unit value, it will be 10616.

Therefore, population density is 10616 people per square mile.

3 0

3 years ago