This problem is simply asking us to add the weights which are presented as fractions. You can easily get the answer if you input them directly in a calculator. But I think the challenge here is to manually add fractions.
Let's add the two 1/4 lb weights because it is easier for they have a common denominator. Just simply add the numerators.
1/4 + 1/4 = 2/4
Then, add with this the fraction part of 2 1/5.
2/4 + 1/5 = ?
The least common denominator is 4*5 = 20. Then divide 20 with each denominator and multiply to their respective numerator.
2/4 + 1/5 = [(20/4 * 2) + (20/5 *1)]/20 = 14/20
14/20 is simplified to 7/10. Then add the whole number 2. <em>Therefore, the sum of all weights is 2 7/10 pounds.</em>
Answer:
Numerator = 2(b^2+a^2) or equivalently 2b^2+2a^2
Denominator = (b+a)^2*(b-a), or equivalently b^3+ab^2-a^2b0-a^3
Step-by-step explanation:
Let
S = 2b/(b+a)^2 + 2a/(b^2-a^2) factor denominator
= 2b/(b+a)^2 + 2a/((b+a)(b-a)) factor denominators
= 1/(b+a) ( 2b/(b+a) + 2a/(b-a)) find common denominator
= 1/(b+a) ((2b*(b-a) + 2a*(b+a))/((b+a)(b-a)) expand
= 1/(b+a)(2b^2-2ab+2ab+2a^2)/((b+a)(b-a)) simplify & factor
= 2/(b+a)(b^2+a^2)/((b+a)(b-a)) simplify & rearrange
= 2(b^2+a^2)/((b+a)^2(b-a))
Numerator = 2(b^2+a^2) or equivalently 2b^2+2a^2
Denominator = (b+a)^2*(b-a), or equivalently b^3+ab^2-a^2b0-a^3
The square root of 16 is 4
The answer is D. 10x-2y-6
Answer:
2 2/3
Step-by-step explanation:
Make them into improper fractions first.
11/2 - 17-6
Then multiply 11/2 so that they have common denominators.
33/6 - 17/6
Then solve.
33/6 - 17/6 = 16/6
Then convert back into a mixed number.
2 4/6 or 2 2/3
