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yuradex [85]
2 years ago
9

Please help WILL MARK BRAINLIEST HURRY LOOK AT PHOTO

Mathematics
2 answers:
Aleks04 [339]2 years ago
5 0

Answer:

I believe it is D I'm a senior in pre-cal but I also dont have paper so I did it in my head rq

Jlenok [28]2 years ago
5 0

Answer:

Option B

\red{ \boxed{ \bold{ {f}^{ - 1} (x) = \sqrt[3]{ - x - 9} }}}

Step-by-step explanation:

f(x) =  -  {x}^{3}  - 9  \\ plug \: f(x) = y \\   \implies \: y =   - {x}^{3}  - 9 \\ interchange \: x \: and \: y \\  \\ x =  -  {y}^{3}  - 9 \\  \\ x + 9 =  -  {y}^{3}  \\  \\  - x - 9 =  {y}^{3}  \\  \\   \sqrt[3]{ - x - 9}  = y \\  \\ \sqrt[3]{ - x - 9} =  {f}^{ - 1} (x) \\  \\ \red{ \boxed{ \bold{ {f}^{ - 1} (x) = \sqrt[3]{ - x - 9} }}}

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<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%20%2B%201%7D%7B2x%20-%201%7D%20%20-%20%20%5Cfrac%7Bx%20-%201%7D%7B2x%20%2B%201%
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