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yuradex [85]
2 years ago
9

Please help WILL MARK BRAINLIEST HURRY LOOK AT PHOTO

Mathematics
2 answers:
Aleks04 [339]2 years ago
5 0

Answer:

I believe it is D I'm a senior in pre-cal but I also dont have paper so I did it in my head rq

Jlenok [28]2 years ago
5 0

Answer:

Option B

\red{ \boxed{ \bold{ {f}^{ - 1} (x) = \sqrt[3]{ - x - 9} }}}

Step-by-step explanation:

f(x) =  -  {x}^{3}  - 9  \\ plug \: f(x) = y \\   \implies \: y =   - {x}^{3}  - 9 \\ interchange \: x \: and \: y \\  \\ x =  -  {y}^{3}  - 9 \\  \\ x + 9 =  -  {y}^{3}  \\  \\  - x - 9 =  {y}^{3}  \\  \\   \sqrt[3]{ - x - 9}  = y \\  \\ \sqrt[3]{ - x - 9} =  {f}^{ - 1} (x) \\  \\ \red{ \boxed{ \bold{ {f}^{ - 1} (x) = \sqrt[3]{ - x - 9} }}}

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3 years ago
Match these similar triangles proof<br>​
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Ok. They are trying to reconstruct the smaller looking triangle in the bigger triangle using angle A as the common angle.

The first statement is always the given.

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