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yuradex [85]
2 years ago
9

Please help WILL MARK BRAINLIEST HURRY LOOK AT PHOTO

Mathematics
2 answers:
Aleks04 [339]2 years ago
5 0

Answer:

I believe it is D I'm a senior in pre-cal but I also dont have paper so I did it in my head rq

Jlenok [28]2 years ago
5 0

Answer:

Option B

\red{ \boxed{ \bold{ {f}^{ - 1} (x) = \sqrt[3]{ - x - 9} }}}

Step-by-step explanation:

f(x) =  -  {x}^{3}  - 9  \\ plug \: f(x) = y \\   \implies \: y =   - {x}^{3}  - 9 \\ interchange \: x \: and \: y \\  \\ x =  -  {y}^{3}  - 9 \\  \\ x + 9 =  -  {y}^{3}  \\  \\  - x - 9 =  {y}^{3}  \\  \\   \sqrt[3]{ - x - 9}  = y \\  \\ \sqrt[3]{ - x - 9} =  {f}^{ - 1} (x) \\  \\ \red{ \boxed{ \bold{ {f}^{ - 1} (x) = \sqrt[3]{ - x - 9} }}}

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As a town gets smaller, the population of its high school decreases by 8% each year. The senior class has 320 students now. In h
Semmy [17]

Answer:

in 13.95 years the senior class will have 100 students.

Step-by-step explanation:

P(h) = p(0.92)^t (equation for exponential change)

P(h) - population of highschool (or senior class) = 100

p - staring amount = 320

t = time in years

100 = 320(0.92)^t

1/3.2 = .92^t (divide both sides by 320)

log(1/3.2, .92) = t (log base 0.92 of 1/3.2 equals t)

13.9497 = t

6 0
2 years ago
A rabbit can run 35 miles per hour.A fox can run 21 miles in half an hour.Which animal is faster and how much
Pachacha [2.7K]

Answer:


Step-by-step explanation:

The fox is faster. Because he is a fox.


Also because he can (assuming he doesn't fatigue or get caught by hounds in the second half of the hour) run 42 miles in 1 hour.


The rabbit runs 35 miler per hour.


Velocity = Distance/time


Fox velocity = 21 miles/0.5 hour


Dividing by 0.5 is the same as multiplying by 2, so...


Fox velocity = 42 miles/hour

6 0
2 years ago
school X and school Y play each other in a competition. School X has eight more points that school Y . School X has three times
Alja [10]
Y = 4
x = 12
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3 years ago
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Angelina_Jolie [31]
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3 years ago
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Lelechka [254]

Answer:

77.  \cot^{6} x = \cot^{4} x \csc^{2}x - \cot^{4} xProved

78.  \sec^{4}x \tan^{2} x = \sec^{2}x [\tan^{2}x + \tan^{4}x ] Proved

79. \cos^{3} x\sin^{2} x = [\sin^{2}x - \sin^{4}x] \cos x Proved.

80. \sin^{4}x - \cos^{4}x = 1 - 2\cos^{2}x + 2 \cos^{4} x Proved.

Step-by-step explanation:

77. Left hand side

= \cot^{6} x

= \cot^{4} x \times \cot^{2} x

= \cot^{4}x [\csc^{2}x - 1]  

{Since we know, \csc^{2} x - \cot^{2}x = 1}

= \cot^{4} x \csc^{2}x - \cot^{4} x  

= Right hand side (Proved)

78. Left hand side

= \sec^{4}x \tan^{2} x

= \sec^{2} x [1 + \tan^{2}x] \tan^{2} x  

{Since \sec^{2}x - \tan^{2}x = 1}

= \sec^{2}x [\tan^{2}x + \tan^{4}x ]

= Right hand side (Proved)

79. Left hand side  

= \cos^{3} x\sin^{2} x

= \cos x[1 - \sin^{2} x] \sin^{2} x

{Since \sin^{2}x + \cos^{2} x = 1}

= [\sin^{2}x - \sin^{4}x] \cos x

= Right hand side

80. Left hand side  

= \sin^{4}x - \cos^{4}x

= [\sin^{2}x + \cos^{2}x]^{2} - 2\sin^{2} x \cos^{2}x

{Since \sin^{2}x + \cos^{2} x = 1}

= 1 - 2\cos^{2} x[1 - \cos^{2}x ]

= 1 - 2\cos^{2}x + 2 \cos^{4} x

= Right hand side. (Proved)

7 0
3 years ago
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