Using Pythagorean theorem, we can justify our answer.
if c^2 = a^2 + b^2 then triangle is right one,
if c^2 > a^2 + b^2 then triangle is obtuse and
if c^2 < a^2 + b^2 then triangle is acute triangle.
Here a=8, b=11 and c=16
Put these values in the equation
16^2 = 8 ^2 + 11^2
256 = 64 +121
256> 185
So here c^2 > a^2 + b^2 Which means triangle is obtuse triangle.
Answer: Obtuse Triangle
Hello! the answer is c
First of all let's eliminate the answers that do not make sense. For A. numbers are NOT irrational because they are a fraction. Numbers are also not irrational because they are a repeating number. C and D are both correct as fractions and terminating decimals are both rational numbers.
34/3≈11.33333333
By using a certain formula you can convert repeating decimals to a fraction. But most people know that .3333333 is 1/3. This gives us 11 1/3 as our answer. So what does it match? It is not a terminating decimal. It repeats but can be written as a fraction. Therefore our answer is C) Rational, because it is a fraction.
I hope this helps!
bran-list please
To check which ordered pair (point) is in the solution set of the system of given linear inequalities y>x, y<x+1; we just need to plug given points into both inequalities and check if that point satisfies both inequalities or not. If any point satisfies both inequalities then that point will be in solution.
I will show you calculation for (5,-2)
plug into y>x
-2>5
which is clearly false.
plug into y<x+1
-2<5+1
or -2<6
which is also false.
hence (5,-2) is not in the solution.
Same way if you test all the given points then you will find that none of the given points are satisfying both inequalities.
Hence answer will be "No Solution from given choices".
I think you mean roll a die. To do this you would find the number of non-even numbers and divide that number by the total amount of numbers on the die. On a normal six-sided die these numbers would be 1,3,and 5, so your probability of not rolling an even number would be 50%
No no yes yes
please mark brainliest
