Answer:
1/3
Step-by-step explanation:
Answer:
12<x<16
Step-by-step explanation:
if c^2 > a^2 + b^2
then the triangle is obtuse
since 20 is the longest side
20^2 > x^2 + (x+4)^2
simplify
400 > x^2 + (x+4)(x+4)
FOIL
400 > (x^2 ) + (x^2 + 4x+4x+16)
combine like terms
400 > (2x^2 + 8x+16)
divide by 2
400/2 > 2x^2 /2 + 8x/2 + 16/2
200 > x^2 + 4x +8
subtract 200 from each side
0> x^2 + 4x +8-200
0> x^2 +4x-192
Factor
0 > (x-12) ( x+16)
using the zero product property
0> x-12 0 > x+16
12>x -16>x
x must be greater than 12
we know the longest side is 20
x+4 < 20
subtract 4
x< 16
x>12 and x < 16
12<x<16
Answer:
-8
Step-by-step explanation:
-40/5=-8
Angle A ~ Angle FEC
Angle B ~ Angle EFC
Angle BDA ~ Angle FCE
AB ~ EF
BD ~ FC
AD ~ EC
(n+5)^2=48
sqrt both sides
n+4=+/-4√3
minus 4 both sides
n=-4+/-4√3
-4+4√3>0 so this cannot be the value of n
n=-4-4√3
the number is -4-4√3
