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Tju [1.3M]
3 years ago
11

A ladder is placed against a wall such that it reaches the top of the wall at a height of 6 meters. The ladder is inclined at an

angle of 60 degrees from the ground. How far is the ladder from the foot of the wall?
(Please show work)

Mathematics
1 answer:
faust18 [17]3 years ago
4 0

Answer:

3.46 meters

Step-by-step explanation:

In the right triangle, Using Trigonometry

\tan 60^\circ = \dfrac{6}{x} \\$Cross multiply\\x\tan 60^\circ =6\\$Divide both sides by \tan 60^\circ\\x=\dfrac{6}{\tan 60^\circ}\\\\x=3.46$ meters

The ladder is 3.46 meters from the foot of the wall.

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A cable hangs between two poles of equal height and 35 feet apart. At a point on the ground directly under the cable and x feet
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Answer:

293.38 pounds

Step-by-step explanation:

We are given that

Distance between poles=35 feet

h(x)=10+0.1(x^{1.5})

Weight of cable=10.4 per linear foot

We have to find the weight of the cable.

Differentiate w.r.t

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s=2\int_{0}^{17.5}\sqrt{1+(h'(x))^2}dx

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s=2\int_{0}^{17.5}\sqrt{1+0.0225x}dx

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dx=\frac{1}{0.0225}dt

s=\frac{2}{0.0225}\int_{0}^{17.5}\sqrt{t}dt

s=\frac{2}{0.0225}\times\frac{2}{3}[t^{\frac{3}{2}}]^{17.5}_{0}

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s=28.21

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The function f(x) is a parabola. We can tell it is a even degree polynomial because the axis of reflection is a vertical line (it passes through the vertex).

In this case, f(x) has a double root at (0,1), but a parabola will have up to 2 roots.

It has a positive leading (quadratic in this case) coefficient, because it is concave up.

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