If a worker makes 600,000 a month, we can multiply that to 12, since there are 12 months in a year. 600,000 x 12 = 72,000,00, so the worker makes $72,000,00 a year. :)
Area is 140 and perimeter is 16
Answer:
From a <u>table</u>, for an ordered pair (0, y), <em>y</em> will not be <u>zero</u>. From a <u>graph</u>, the y-intercept will not be <u>zero</u>. From an equation, it will have the form, y = mx + b where b is <u>≠ 0</u>.
Step-by-step explanation:
- From a <u>table</u>, for an ordered pair (0, y), <em>y</em> will not be <u>zero</u>. If there is not a constant rate of change in the data displayed in a table, then the table represents a nonlinear nonproportional relationship.
- From a <u>graph</u>, the y-intercept will not be <u>zero</u>. This means that it doesn't contain or go through the origin.
- From an equation, it will have the form, y = mx + b where b is <u>≠ 0.</u> (not equal to zero). If an equation is not a linear equation, it represents a nonproportional relationship. A <u>linear equation</u> of the form y = mx + b may represent either a <em>proportional</em> (b = 0) or <em>nonproportional</em> (b ≠ 0) relationship. Therefore, when b ≠ 0, the relationship between <em>x</em> and <em>y</em> is <u>nonproportional</u>.
Answer:
The inequality that could be used is 8.50p≤300 and the greatest number of people that can attend is 35.
Step-by-step explanation:
From the information provided, you can write an inequality where total cost for people attending at the party should be less than or equal to $300:
3.50p+5.00p≤300
8.50p≤300
Now, you can solve for p:
p≤300/8.50
p≤35
According to this, the answer is that the inequality that could be used is 8.50p≤300 and the greatest number of people that can attend is 35.
Answer:
The approximate cost during the year 1987 was $7,533
Step-by-step explanation:
The complete question in the attached figure
we have
y -----> is the cost in dollars
x -----> is the year
Looking at the graph we have the points
(1983,5,047) and (1991, 10,019)
To determine the cost in the year 1987, find out the midpoint between the two given points
The formula to calculate the midpoint between two points is equal to

substitute the values


therefore
The approximate cost during the year 1987 was $7,533