Solve the equation x to the second power - 13x to the third power + 47x -35=0 given that 1 is a zero of f(x) = x to the third po
wer-13x to the second power+ 47x-35. The solution set is?
1 answer:
Answer:
The solution sets are 1, 5 and 7
Step-by-step explanation:
Given the polynomial function,
f(x) = x³-13x²+47x-35
If 1 is a zero function of f(x), according to factor theorem, the linear equation x-1 is a factor of the polynomial.
To get the other solution set, we will have to divide the polynomial function by x-1 and factorize the quotient function.
Factorising the resulting quotient function.
Q(x) = x²-12x+35 = 0
= x²-5x-7x+35 = 0
= x(x-5)-7(x-5) = 0
(x-5)(x-7) = 0
x-5 = 0 and x-7 = 0
x = 5 and 7
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Answer:
x = 10
Step-by-step explanation:
Using the rules of logarithms
• log x + log y ⇔ log(xy)
• log ⇔ n log x
• log x = log y ⇒ x = y
Given
ln20 + ln5 = 2 lnx , then
ln(20 × 5) = ln
ln 100 = ln, hence
x² = 100 ( take the square root of both sides )
x = 10