For the answer to the question above,
1 + nx + [n(n-1)/(2-factorial)](x)^2 + [n(n-1)(n-2)/3-factorial] (x)^3
<span>1 + nx + [n(n-1)/(2 x 1)](x)^2 + [n(n-1)(n-2)/3 x 2 x 1] (x)^3 </span>
<span>1 + nx + [n(n-1)/2](x)^2 + [n(n-1)(n-2)/6] (x)^3 </span>
<span>1 + 9x + 36x^2 + 84x^3 </span>
<span>In my experience, up to the x^3 is often adequate to approximate a route. </span>
<span>(1+x) = 0.98 </span>
<span>x = 0.98 - 1 = -0.02 </span>
<span>Substituting: </span>
<span>1 + 9(-0.02) + 36(-0.02)^2 + 84(-0.02)^3 </span>
<span>approximation = 0.834 </span>
<span>Checking the real value in your calculator: </span>
<span>(0.98)^9 = 0.834 </span>
<span>So you have approximated correctly. </span>
<span>If you want to know how accurate your approximation is, write out the result of each in full: </span>
<span>1 + 9(-0.02) + 36(-0.02)^2 + 84(-0.02)^3 = 0.833728 </span>
<span> (0.98)^9 = 0.8337477621 </span>
<span>So it is correct to 4</span>
Answer:
b=-2
Step-by-step explanation:
3√-8 = -2
-2^3 = -8
Hey there!
We know that Danielle earns $10 per hour, so muliply that by 3 and get 30.
Because Danielle works an extra half an hour, divide 10 by 2 and get 5.
Danielle earns $35 in 3 hours and a half.
Hope this helps! Please mark me as brainliest!
Have a wonderful day :)
I FOUND YOUR COMPLETE QUESTION IN OTHER SOURCES.
SEE ATTACHED IMAGE.
For this case what you need to know is how much tape Alex needs.
We have then:
"He needs 7 sections of ribbon with a length of 3/4 yard"
In other words:
(7) * (3/4) = 5.25 yards.
Therefore, the amount of tape that will be left over will be:
30.2-5.25 = 24.95 yards.
Answer:
after Alex cuts the 7 pieces will remain 24.95 yards of ribbon
Answer:
23.6 Repeated
Step-by-step explanation: