Answer:

Step-by-step explanation:
solving for dy/dx
multiply the equation out to remove parentheses

now differentiating in terms of x (
)

isolating dy/dx to one side



Answer:
y=3x-2
Step-by-step explanation:
The formula for slope is y=mx=b
You can find the slope by finding two points that lie on the line (1,1) & (0,-2)
The formula for slope is 
You plug the values in and you get 
Simplify and you get 3
The slope is 3
The y-intercept (b) is -2
Its may be A or C
i am not sure just try to help
Answer:



Arithmetic sequence
Step-by-step explanation:
We are given that
A(1)=9
We have to find first three terms and identify the sequence is geometric or arithmetic.
Substitute n=1
Then, we get

For n=2

For n=3





When the difference of consecutive terms are constant then the sequence is arithmetic sequence.
Therefore, given sequence is arithmetic sequence.
The parametric equations for x and y describe a circle of radius 10 m, so the length of the base of the fence is the length of the circumference of a circle of radius 10 m. The formula for that circumference (C) is ...
... C = 2πr
... C = 2π·(10 m) = 20π m
The height as a function of angle (t) is found by substituting for x and y.
... h(t) = h(x(t), y(t)) = 4 + 0.01·((10cos(t))²-)10sin(t))²) = 4+cos(2t)
The average value of this over the range 0 ≤ t ≤ 2π is 4, since the cosine function has two full cycles in that range, and its average value over a cycle is zero.
Thus, the area of one side of the fence is that of a rectangle 20π m long and 4 m wide. That will be
... (20π m)·(4 m) = 80π m²
The amount of paint required to cover both sides of the fence is
... 2×(80π m²)×(1 L)/(10 m²) = 16π L ≈ 50.3 L
_____
You can work out the integral for area as a function of t. When you do, you will find it gives this same result.