Answer:
x > -1.25
Step-by-step explanation:
First, let's start with the left side of the equation.
1) multiply 0.2(x + 20). You will get 0.2x+4
So you have 0.2x+4-3
Simplify that, you will have 0.2x+1
Now, we need to isolate the variable (bring all terms with "x" to one side), and move everything else to another side. Remember that when you bring something to the other side, you must change the sign in front of the term (for example, bringing 2x to another side would change it to -2x. another example is if you were to bring -2 to another side, you would have to change it to 2.)
2) 0.2x+6.2x>-7-1 Moved like terms to one side.
6.4x>-8 I combined the terms here!
x > -1.25 Simplified!
Let me know if you need anything else :)
FORMULA:
ANSWER:
We are given new side of square i.e, 2s + 3.
So, Area = (2s + 3)²
- (2s)² + (3)² + 2 × 2s × 3
- 4s² + 9 + 12s
Hence, The area of the new graph is a perfect square trinomial: __4__s² + __12__s +__9__.
The best answer i think would get is C i hope im right
Answer:
C would be equal to (f - 13)/(10 - d)
Step-by-step explanation:
In order to find this, you must manipulate the equation so that the left side has every term with a c in it. Then you can isolate it by dividing and find what it is equal to.
10c - f = -13 + cd -----> Add f to both sides
10c = f - 13 + cd -----> Subtract cd from both sides
10c - cd = f - 13 ------> Pull out c
c(10 - d) = f - 13 -----> Divide by (10 - d)
c = (f - 13)/(10 - d)
Answer: 63lbs
Step-by-step explanation:
The truck can only hold 16crates and each crate weigh 12lbs, the total weight of the 16 crates will be 12×16= 192lbs
This shows that the truck can only contain extra load of 1200lbs - 192lbs = 1008lbs (excluding weight of crates).
To get the shipment weigh close to the total of 1200lbs, the truck must be loaded with engine components not more than 1008lbs.
Since we have 16 crates to fill with engine components not more than 1008lb, each crates will therefore must not exceed 1008/16 pounds of engine components which is equivalent to 63lbs.
Therefore, the manager should instruct the workers to put 63lbs of machine components in "each crate" in order to get the shipment weight as close as possible to 1200 lbs.
