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2 years ago

Which bottle of water costs more per ounce: a 12

Mathematics

1 answer:

ollegr [7]2 years ago

3 0

Answer:

the second bottle

Step-by-step explanation:

To get the amount it costs per ounce, divide the amount of money by the number of ounces.

A water bottle that costs $1.25 for 12 ounces costs roughly 10 cents per ounce. A water bottle that costs about 9 cents per ounce.

therefore, the 16 ounce bottle is cheaper per ounce

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What is the degree of the function f(x)=x⁴-5x+8+x²?

DENIUS [597]

First put it in decreasing power according to x.

x^4-5x+8+x^2

=x^4+x^2-5x+8

Now this question is asking what is the highest degree of x you see in this function.

4 of course.

Therefore the answer to his question is degree of 4.

Done!

7 0

3 years ago

How to solve the system of equation 500y-600x=2800 , 400y-400x=2400 by elimination

tatiyna

Answer:

$x=2$ and $y=8$

Step-by-step explanation:

Given:

Equation 1:

$500y-600x=2800$

Simplifying the above equation by dividing both sides by 100

$\frac{500y-600x}{100}=\frac{2800}{100}$

$\frac{500y}{100}-\frac{600x}{100}=28\\\\5y-6x=28$

Equation 2:

$400y-400x=2400$

Simplifying the above equation by dividing both sides by 400.

$\frac{400y-400x}{400}=\frac{2400}{400}$

$\frac{400y}{400}-\frac{400x}{400}=6\\\\y-x=6$

Now the system of equation is:

(1a) $5y-6x=28$

(2a) $y-x=6$

Solving by elimination

Multiplying equation (2a) with $-5$

$-5(y-x)=-5\times 6$

(2b) $-5y+5x=-30$

Adding equations (1a) and (2b) in order to eliminate $y$

$5y-6x=28$

+ $-5y+5x=-30$

We get $-x=-2$

∴ $x=2$

Plugging $x=2$ in equation (2a).

$y-2=6$

Adding $2$ both sides.

$y-2+2=6+2$

∴ $y=8$

7 0

3 years ago

HELPP!!

SSSSS [86.1K]

Answer:

There are 15 integers between 2020 and 2400 which have four distinct digits arranged in increasing order.

Step-by-step explanation:

This can be obtained by after a simple counting of number from 2020 and 2400 as follows:

The first set of integers are:

2345, 2346, 2347, 2348, and 2349.

Therefore, there are 6 integers in first set.

The second set of integers are:

2356, 2357, 2358, and 2359.

Therefore, there are 4 integers in second set.

The third set of integers are:

2367, 2368, and 2369.

Therefore, there are 3 integers in third set.

The fourth set of integers are:

2378, and 2379.

Therefore, there are 2 integers in fourth set.

The fifth and the last set of integer is:

2389

Therefore, there is only 1 integers in fifth set.

Adding all the integers from each of the set above, we have:

Total number of integers = 6 + 4 + 3 + 2 + 1 = 15

Therefore, there are 15 integers between 2020 and 2400 which have four distinct digits arranged in increasing order.

7 0

3 years ago

HELP ASAP DUE IN 5!!!!

stellarik [79]

1/5 using the slope formula

7 0

3 years ago

A person invested $7,400 in an account growing at a rate allowing the money to

Reil [10]

Answer:

well the money doubles every 6 years but its only been 4 so

7,400 x 4 = 29,600

$29,600 is the answer

8 0

2 years ago