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irakobra [83]
2 years ago
6

How to find the missing lengths of a partelogram

Mathematics
1 answer:
Levart [38]2 years ago
6 0

Answer:

Below.

Step-by-step explanation:

The area = the height (h) times the base.

So Q2:

21 = h * 7

h = 21/7 = 3

55 = b * 5

b = 11.

18.75 = h * 7.5

h = 18.75 / 7.5

= 2.5.

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A pulley is used to pull a boat to the dock. The rope is attached to the boat 7 feet below the level of the pulley. What is the
Svetradugi [14.3K]

Answer: 24 ft

Step-by-step explanation:

By the Pythagorean theorem,

7^{2}+x^{2}=25^{2} \\ \\ 49+x^{2}=625 \\ \\ x^{2}=576 \\ \\ x=\boxed{24 \text{ ft}}

7 0
1 year ago
I need help is it A B C Or D
Anarel [89]
Natural selection <span>is the process where organisms are more likely to reproduce. When they reproduce, they pass on traits to the next generation. Over time this process allows organisms to adapt to their environment. Giving what natural selection means, I believe the answer is D. Evolution does NOT always improve organisms. 

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3 years ago
Find integrate (1/(xsqrt(1+(lnx)^2)),1,e,x) ...?
prohojiy [21]
Note that x² + 2x + 3 = x² + x + 3 + x. So your integrand can be written as 

<span>(x² + x + 3 + x)/(x² + x + 3) = 1 + x/(x² + x + 3). </span>

<span>Next, complete the square. </span>

<span>x² + x + 3 = x² + x + 1/4 + 11/4 = (x + 1/2)² + (√(11)/2)² </span>

<span>Also, for the x in the numerator </span>

<span>x = x + 1/2 - 1/2. </span>

<span>So </span>

<span>(x² + 2x + 3)/(x² + x + 3) = 1 + (x + 1/2)/[(x + 1/2)² + (√(11)/2)²] - 1/2/[(x + 1/2)² + (√(11)/2)²]. </span>

<span>Integrate term by term to get </span>

<span>∫ (x² + 2x + 3)/(x² + x + 3) dx = x + (1/2) ln(x² + x + 3) - (1/√(11)) arctan(2(x + 1/2)/√(11)) + C </span>

<span>b) Use the fact that ln(x) = 2 ln√(x). Then put u = √(x), du = 1/[2√(x)] dx. </span>

<span>∫ ln(x)/√(x) dx = 4 ∫ ln u du = 4 u ln(u) - u + C = 4√(x) ln√(x) - √(x) + C </span>

<span>= 2 √(x) ln(x) - √(x) + C. </span>

<span>c) There are different approaches to this. One is to multiply and divide by e^x, then use u = e^x. </span>

<span>∫ 1/(e^(-x) + e^x) dx = ∫ e^x/(1 + e^(2x)) dx = ∫ du/(1 + u²) = arctan(u) + C </span>

<span>= arctan(e^x) + C.</span>
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