There are 10 in total
3/10 x 2/9 = 6/90
Reduce
1/15
1/15 is the chance of that happening
Answer: 0.2
Step-by-step explanation:
a. Use the inclusion/exclusion principle.

b. By definition of conditional probability,

Since d x pi = circumference
I use 3.14 as pie
I did 9 x pi = 28.26 I DID NOT divide this by two because there are three half circles and 28.26 counts as two of them
Since there is another half circle I divide 28.26 by 2
28.26 + 14.13 = 42.39
Now plus the bottom length
42.39 + 9 = 51.39
Brainliest answer please?