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Orlov [11]
3 years ago
15

How Do I do this? What’s the Answer?

Mathematics
1 answer:
frez [133]3 years ago
3 0
F(x) = 5x

for f(7) you replace x with 7 so it will be : f(7) = 5(7) = 35
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Find the quotient of and express it in the simplest form
nirvana33 [79]

Answer:

No answer can be found

Step-by-step explanation:

There isn't any value to find and express in simplest form lol.

5 0
3 years ago
Please help, see attachment for equation!
Alekssandra [29.7K]

Answer:

The answer to your question is the last option

Step-by-step explanation:

Quadratic equation

                                2 = - x + x² - 4

Order the equation from the highest power to the lowest power. Do not consider 2 because it is not consider in the options given.

                               x² - x - 4  = 0

Identify a, b and c

                              (1) x² -(1) x - 4 = 0

    a = 1    b = -1    c = - 6      

Substitution              

                              \frac{-(-1) +- \sqrt{(-1)^{2} - 4(1)((-4)}}{2(1)}

3 0
3 years ago
The number of chocolate chips in a bag of chocolate chip cookies is approximately normally distributed with mean of 1262 and a s
Andrew [12]

Answer:

a) 1186

b) Between 1031 and 1493.

c) 160

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Normally distributed with mean of 1262 and a standard deviation of 118.

This means that \mu = 1262, \sigma = 118

a) Determine the 26th percentile for the number of chocolate chips in a bag. ​

This is X when Z has a p-value of 0.26, so X when Z = -0.643.

Z = \frac{X - \mu}{\sigma}

-0.643 = \frac{X - 1262}{118}

X - 1262 = -0.643*118

X = 1186

(b) Determine the number of chocolate chips in a bag that make up the middle 95% of bags.

Between the 50 - (95/2) = 2.5th percentile and the 50 + (95/2) = 97.5th percentile.

2.5th percentile:

X when Z has a p-value of 0.025, so X when Z = -1.96.

Z = \frac{X - \mu}{\sigma}

-1.96 = \frac{X - 1262}{118}

X - 1262 = -1.96*118

X = 1031

97.5th percentile:

X when Z has a p-value of 0.975, so X when Z = 1.96.

Z = \frac{X - \mu}{\sigma}

1.96 = \frac{X - 1262}{118}

X - 1262 = 1.96*118

X = 1493

Between 1031 and 1493.

​(c) What is the interquartile range of the number of chocolate chips in a bag of chocolate chip​ cookies?

Difference between the 75th percentile and the 25th percentile.

25th percentile:

X when Z has a p-value of 0.25, so X when Z = -0.675.

Z = \frac{X - \mu}{\sigma}

-0.675 = \frac{X - 1262}{118}

X - 1262 = -0.675*118

X = 1182

75th percentile:

X when Z has a p-value of 0.75, so X when Z = 0.675.

Z = \frac{X - \mu}{\sigma}

0.675 = \frac{X - 1262}{118}

X - 1262 = 0.675*118

X = 1342

IQR:

1342 - 1182 = 160

7 0
3 years ago
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cestrela7 [59]

the answer is 1/10 :))))))))

7 0
2 years ago
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Find the equation of the line shown.
dedylja [7]

Answer:

f(x)=2x

Step-by-step explanation:

You can get your (a)term by finding rise/run, and there is no y-intercept so the (b)term is not known. Thus you get f(x)=2x.

8 0
2 years ago
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