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Alinara [238K]
2 years ago
11

4.Explain why digital signals are somewhat harder to hack or spy on than analog signals​

Physics
1 answer:
SCORPION-xisa [38]2 years ago
6 0

Answer:

1activates the signal, whereas a zero deactivates it. Like light switches, digital signals have two values. Digital signals deliver chunks, but analog transmissions send continuous streams.

2Unlike analog signals, which may transmit an endless number of values, digital signals can only convey two different values. A popular digital signal is binary code, which is a language made up entirely of zeros and ones that computers use to communicate.

3In binary form, the binary system manipulates discrete data. Modulating or encoding digital signals can also be used to represent binary data. A discrete signal is referred to as a digital signal. The signal is continuous.

Explanation:

man idek

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The correct answer is D. The movement of the molecules will gradually increase.

Explanation:

At the beginning of the model the state of matter of the water is solid, in this, particles have a defined arrangement and are together, which stops particles from moving freely and only allows them to vibrate. However, as the substance is heated the thermal energy (heat) increases in the sample, this causes particles to move more and the arrangement of it changes. Due to this, when the ice melts and there is liquid water particles move more than in solid states, which makes ice lacks a defined shape. Moreover, as the heat continues to increase the thermal and kinetic energy (movement) increases, indeed in gas state (water vapor) particles will move freely. This means the movement or kinetic energy in particles gradually increases in the model.

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4 years ago
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3 years ago
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A car is traveling at 100 km/h when the driver sees an accident 80 m ahead and slams on the brakes. what minimum constant decele
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Assuming the driver starts slamming the brakes immediately, the car moves by uniformly decelerated motion, so we can use the following relationship
2aS = v_f^2 - v_i^2 (1)
where 
a is the deleceration
S is the distance covered after a time t
v_f is the velocity at time t
v_i=100 km/h = 27.8 m/s is the initial speed of the car

The accident is 80 m ahead of the car, so the minimum deceleration required to avoid the accident is the value of a such that S=80 m and v_f=0 (the car should stop exactly at S=80 m to avoid the accident). Using these data, we can solve  the equation (1) to find a:
a=- \frac{v_i^2}{2 S}= -\frac{(27.8 m/s)^2}{2 \cdot 80 m} =-4.83 m/s^2
And the negative sign means it is a deceleration.

4 0
4 years ago
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