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damaskus [11]
4 years ago
9

If the distance from a converging lens to the object is less than the focal length of the lens, the image will be _______ the ob

ject. A. real, inverted, and larger than B. real, inverted, and smaller than C. virtual, upright, and smaller than D. virtual, upright, and larger than
Physics
2 answers:
VLD [36.1K]4 years ago
6 0
<span>virtual, upright, and larger than. just took the test

</span>
slega [8]4 years ago
5 0

Answer;

D. virtual, upright, and larger than

Explanation;

-Real images are those where light actually converges, whereas virtual images are locations from where light appears to have converged. Real images occur when objects are placed outside the focal length of a converging lens or outside the focal length of a converging mirror.

-The image happens to be larger than the object. That happens because the object is between f and 2f away from the lens; if the lens were farther away than 2f, the image would be closer to the lens than 2f, and would be smaller than the object.

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A car travels 70 km in two hours 104 km in the next 1.5 hours and then 79 km in two hours before reaching its destination what w
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Average speed = (total distance) / (total time)

Total distance = (70km + 104km + 79km) = 253 km

Total time = (2hr + 1.5hr + 2hr) = 5.5 hrs

Average speed = (253 km) / (5.5 hrs)

<em>Average speed = 46 km/hr</em>

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4 years ago
A rocket in orbit just above the atmosphere is moving in uniform circular motion. The radius of the circle in which it moves is
Zinaida [17]
Centripetal acceleration is given by the formula

a_{cen}= \frac{v^2}{r}

Since we know the value of the acceleration is 9.8 m/s² and we know r, we can solve for the speed, which is the magnitude of v.  Note the value of a is just the acceleration due to gravity, which is what makes the rocket orbit and not fly off into space.

9.8 \frac{m}{s^2}=\frac{v^2}{6.381 \times 10^6m}   \\  \\ 9.8 \frac{m}{s^2} \times 6.381 \times 10^6m=v^2 \\  \\ v= \sqrt{9.8 \frac{m}{s^2} \times 6.381 \times 10^6m} =24755 \frac{m}{s}
8 0
3 years ago
Where would you most likely find regional metamorphism? associated with a mountain belt associated with a volcano associated wit
vladimir1956 [14]
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Answer: You would most likely find regional metamorphism associated with a mountain belt.

5 0
3 years ago
Read 2 more answers
Tailor your business to aim your product or service at a certain group of customers, who are called the
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4 years ago
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A car initially traveling at 27.2 m/s undergoes a constant negative acceleration of magnitude 1.90 m/s2 after its brakes are app
zubka84 [21]

Answer:

Therefore, the revolutions that each tire makes is:

\Delta \theta=22\: rev

Explanation:

We can use the following equation:

\omega_{f}^{2}=\omega_{i}^{2}-2\alpha \Delta \theta (1)

The angular acceleration is:

a_{tan}=\alpha R

\alpha=\frac{1.9}{0.325}

\alpha=5.85\: rad/s^{2}

and the initial angular velocity is:

\omega_{i}=\frac{v}{R}

\omega_{i}=\frac{27.2}{0.325}

\omega_{i}=83.69\: rad/s

Now, using equation (1) we can find the revolutions of the tire.

0=83.69^{2}-2*25.85 \Delta \theta

\Delta \theta=135.47\: rad

Therefore, the revolutions that each tire makes is:

\Delta \theta=22\: rev

I hope it helps you!

6 0
3 years ago
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