2. Which animal is a primary consumer in the Ethiopian Highlands?
2 answers:
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<h2>Answer:</h2>
The rate of deceleration is -0.14
Using one of the equations of motion;
v = u + at
where;
v = final velocity of the boat = 0m/s (since the boat decelerates to a stop)
u = initial velocity of the boat = 25m/s
a = acceleration of the boat
t = time taken for the boat to accelerate/decelerate from u to v = 3 minutes
<em>Convert the time t = 3 minutes to seconds;</em>
=> 3 minutes = 3 x 60 seconds = 180seconds.
<em>Substitute the values of v, u, t into the equation above. We have;</em>
v = u + at
=> 0 = 25 + a(180)
=> 0 = 25 + 180a
<em>Make a the subject of the formula;</em>
=> 180a = 0 - 25
=> 180a = -25
=> a = -25/180
=> a = -0.14
The negative value of a shows that the boat is decelerating.
Therefore, the rate of deceleration of the speed boat is 0.14
Answer:
Please see attachment
Explanation:
Please see attachment
Answer:
The heat capacity of a sample is 37.7 J/K.
Explanation:
Given that,
Submerged temperature of tissue sample = 275 K
Mass of liquid nitrogen= 2 kg
Temperature = 70 K
Final temperature = 75 K
We need to calculate the heat
Using formula of heat
Put the value into the formula
We need to calculate the heat capacity of a sample
Using formula of heat capacity
Put the value into the formula
Hence, The heat capacity of a sample is 37.7 J/K.